我在MYSQL中创建了一个查询,如下所示:
select subsql.item_id, subsql.uid, subsql.post_date, subsql.uid_prev,
max(workflow_trans.date) AS pre_date
from (
select item_id, max(date) AS post_date, uid, uid_prev
from workflow_trans
where uid = 'name' and date <= 'date1' and date >= 'date2'
group by item_id, uid, uid_prev
) AS subsql
left join workflow_trans on subsql.item_id = workflow_trans.item_id and
subsql.uid_prev = workflow_trans.uid and subsql.post_date > workflow_trans.date
where workflow_trans.date is not null
group by subsql.item_id, subsql.uid, subsql.post_date, subsql.uid_prev
order by subsql.post_date
In将其翻译成Zend DB格式如下:
$this->db->select()->from(array("subsql" => $this->db->select()
->from(array($this->_name), array('item_id', 'max(date) AS post_date',
'uid', 'uid_prev'))
->where("uid = ?", $username)->where("date >= ?", $tgl1)
->where("date <= ?", $tgl2)
->group(array('item_id', 'uid', 'uid_prev'))),
array('subsql.item_id','subsql.uid',
'subsql.post_date','subsql.uid_prev','max(workflow_trans.date)
as pre_date'))
->joinLeft($this->_name, 'subsql.item_id = workflow_trans.item_id
and subsql.uid_prev = workflow_trans.uid and subsql.post_date >
workflow_trans.date')
->where("workflow_trans.date != ?", null)
->group(array('subsql.item_id', 'subsql.uid', 'subsql.post_date',
'subsql.uid_prev'))
->order(array('subsql.post_date'))
然而,Zend模型无法运作。我已经对它进行了重新检查,并进行了3次更改,但格式仍有问题。新的一双锐利的眼睛是赞赏的。
答案更新
大家好,我已经找到它,在运行代码下面:
$this->db->select()->from(array("subsql" => $this->db->select()
->from(array($this->_name), array('item_id', 'max(date) AS post_date',
'uid', 'uid_prev'))
->where("uid = ?", $username)->where("date >= ?", $tgl1)
->where("date <= ?", $tgl2)
->group(array('item_id', 'uid', 'uid_prev'))),
array('subsql.item_id','subsql.uid','subsql.post_date','subsql.uid_prev'))
->joinLeft(array($this->_name), 'subsql.item_id = workflow_trans.item_id and
subsql.uid_prev = workflow_trans.uid and
subsql.post_date > workflow_trans.date',
array('max(workflow_trans.date) as pre_date'))
->where("workflow_trans.date is not null")
->group(array('subsql.item_id', 'subsql.uid', 'subsql.post_date',
'subsql.uid_prev'))
->order(array('subsql.post_date'));
你应该在自己的join函数中定义连接表中的列,当然我对如何处理null有错误。
如果我们讨论zf3,这个查询会生成与你的相同的sql。
$from = $this->getSql()->select('workflow_trans')
->columns(['item_id, max(date) AS post_date, uid, uid_prev', new Literal('max(workflow_trans.date) AS pre_date')])
->where(['uid = ?' => 'name'])
->where(['date <= ?' => 'date1'])
->where(['date >= ?' => 'date2'])
->group(['item_id', 'uid', 'uid_prev']);
$query = $this->getSql()->select()
->columns(['item_id, uid, post_date, uid_prev'])
->from(['subsql' => $from])
->join('workflow_trans', 'subsql.item_id = workflow_trans.item_id and subsql.uid_prev = workflow_trans.uid and subsql.post_date > workflow_trans.date', [])
->where(new IsNotNull('workflow_trans.date'))
->group(['subsql.item_id', 'subsql.uid', 'subsql.post_date', 'subsql.uid_prev'])
->order('subsql.post_date');