按周javascript分组日期

Question

我有一系列波斯日期，我想按周分组日期。例如，我有以下数组：

[
    "1396-10-11 09:07:21",
    "1396-10-10 10:03:51",
    "1396-10-07 02:07:02",
    "1396-11-27 08:02:45",
    "1396-11-19 01:02:32",
    "1396-12-01 22:13:21",
    "1396-02-12 09:07:21",
    "1396-05-18 04:02:29",
    "1396-05-21 14:01:42",
    "1396-07-11 01:16:29"
]

我希望按周分组日期。

我写了以下代码，但效果不佳：

Array.prototype.groupBy = function(prop) {
  return this.reduce(function(groups, item) {
    var val = item[prop];
    groups[val] = groups[val] || [];
    groups[val].push(item);
    return groups;
  }, {});
}

const formatted = dates.map(elem => {
  return { 
    numberOfWeek: moment(elem.date, 'jYYYY-jMM-jDD').startOf('jMonth').jWeek(),
    date: moment(elem.date, 'jYYYY-jMM-jDD').format('jYYYY-jMM-jDD'), 
    score: elem.score 
  };
});

Answer 1

使用moment().week()获取一年中的周数，然后按其分组，这是一个工作示例，我使用array.reduce创建一个新的对象，其日期按周编号分组：

var dates = [
  "1396-10-11 09:07:21",
  "1396-10-10 10:03:51",
  "1396-10-07 02:07:02",
  "1396-11-27 08:02:45",
  "1396-11-19 01:02:32",
  "1396-12-01 22:13:21",
  "1396-02-12 09:07:21",
  "1396-05-18 04:02:29",
  "1396-05-21 14:01:42",
  "1396-07-11 01:16:29"
];

var groups = dates.reduce( function (acc, date) {

  var yearWeek = moment(date).year()+'-'+moment(date).week();
  
  // check if the week number exists
  if (typeof acc[yearWeek] === 'undefined') {
    acc[yearWeek] = [];
  }
  
  acc[yearWeek].push(date);
  
  return acc;

}, {});

console.log(groups);

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