如何使用 Selenium python webdriver 查找损坏的链接？

Question

我试图在 Selenium 和 Python 中找到损坏的链接，但在代码中出现错误：

import requests
from selenium import webdriver

chrome_driver_path = "D:\\drivers\\chromedriver.exe"

driver=webdriver.Chrome(chrome_driver_path)

driver.get('https://google.co.in/')
links = driver.find_elements_by_css_selector("a")
images = driver.find_elements_by_css_selector("img")
for link in links:
    r = requests.head(link.get_attribute('href')
    print(r.status_code == 200)

无法在页面上找到损坏的链接是否有其他解决方案？

获取：

引发 MaxRetryError(_pool, url, error 或 ResponseError(cause)) urllib3.exceptions.MaxRetryError： HTTPSConnectionPool（主机='myaccount.google.com'，端口=443）：最大 url 重试次数超出：/?utm_source=OGB&utm_medium=app（由 SSLError(SSLEOFError(8, 'EOF 发生违反协议 (_ssl.c:777)'),))

在处理上述异常的过程中，又发生了一个异常：

self._sslobj.do_handshake() ssl.SSLEOFError: EOF 发生违规 协议 (_ssl.c:777)

在处理上述异常的过程中，又发生了一个异常：

回溯（最近一次调用最后一次）：

Answer 1

要查找页面上链接的状态，您可以使用以下解决方案：

• 代码块：

  import requests
  from selenium import webdriver
  
  options = webdriver.ChromeOptions() 
  options.add_argument("start-maximized")
  options.add_argument('disable-infobars')
  driver=webdriver.Chrome(chrome_options=options, executable_path=r'C:\Utility\BrowserDrivers\chromedriver.exe')
  driver.get('https://google.co.in/')
  links = driver.find_elements_by_css_selector("a")
  for link in links:
      r = requests.head(link.get_attribute('href'))
      print(link.get_attribute('href'), r.status_code)
  

• 控制台输出：

  https://mail.google.com/mail/?tab=wm 302
  https://www.google.co.in/imghp?hl=en&tab=wi 200
  https://www.google.co.in/intl/en/options/ 301
  https://myaccount.google.com/?utm_source=OGB&utm_medium=app 302
  https://www.google.co.in/webhp?tab=ww 200
  https://maps.google.co.in/maps?hl=en&tab=wl 302
  https://www.youtube.com/?gl=IN 200
  https://play.google.com/?hl=en&tab=w8 302
  https://news.google.co.in/nwshp?hl=en&tab=wn 301
  https://mail.google.com/mail/?tab=wm 302
  https://www.google.com/contacts/?hl=en&tab=wC 302
  https://drive.google.com/?tab=wo 302
  https://www.google.com/calendar?tab=wc 302
  https://plus.google.com/?gpsrc=ogpy0&tab=wX 302
  https://translate.google.co.in/?hl=en&tab=wT 200
  https://photos.google.com/?tab=wq&pageId=none 302
  https://www.google.co.in/intl/en/options/ 301
  https://docs.google.com/document/?usp=docs_alc 302
  https://books.google.co.in/bkshp?hl=en&tab=wp 200
  https://www.blogger.com/?tab=wj 405
  https://hangouts.google.com/ 302
  https://keep.google.com/ 302
  https://earth.google.com/web/ 200
  https://www.google.co.in/intl/en/options/ 301
  https://accounts.google.com/ServiceLogin?hl=en&passive=true&continue=https://www.google.co.in/ 200
  https://www.google.co.in/webhp?hl=en&sa=X&ved=0ahUKEwj0qNPqnqHbAhXYdn0KHXpeAo0QPAgD 200
  

Answer 2

因为您在下面的行中缺少右括号或者是拼写错误？

r = requests.head(link.get_attribute('href'))

Answer 3

from selenium import webdriver
chrome_driver_path = "D:\\drivers\\chromedriver.exe"
driver=webdriver.Chrome(chrome_driver_path)
import requests
for link in links:
    r = requests.head(link)
    if r.status_code!=404:
         driver.get(link)
    else:
          print(str(link) + " isn't available.")