我有一个 ASP.NET 应用程序,其中页面中有一个产品列表,其中包含相关详细信息和状态列(位字段 - 复选框)。它工作得很好,我可以使用 Ajax 将状态从 true 更改为 false,反之亦然。这样做时,我保持复选框的状态意味着如果它为真,则它保持选中状态,否则保持未选中状态。请参见下图,除了红色突出显示的部分(还有一件事 - True 表示处于活动状态,False 表示在这种情况下处于非活动状态):
现在我正在尝试的是将复选框也变成切换开关,以保持复选框的更改,如下所示 - BootStrap Toggle Switches
我不知道该怎么做,并尝试遵循此操作,使用如下类使复选框用作切换开关 - jQuery 切换开关
<script>
$(document).ready(function () {
$('.toggle-checkbox').btnSwitch({
Theme: 'Light',
OnText: "On",
OffText: "Off",
OnValue: true,
OffValue: false
});
});
</script>
注意: 我必须保留图像中显示的复选框的状态,这些状态不是像“true”、“checked”那样以红色突出显示,反之亦然。我很高兴知道是否可以使用拨动开关执行相同的操作。
数据库脚本:
CREATE TABLE [dbo].[Products](
[Id] [int] IDENTITY(1,1) PRIMARY KEY,
[ProductName] [nvarchar](MAX) NOT NULL,
[Time_Posted] [nvarchar](MAX) NOT NULL,
[Status] [bit] NOT NULL
)
INSERT INTO Products VALUES
('Denim', '7:30:10 PM', 1),
('Pringles', '8:00:00 PM', 1)
型号:
public class Product
{
public int Id { get; set; }
public string ProductName{ get; set; }
public string Time_Posted { get; set; }
public bool Status { get; set; }
}
控制器:
//Get details of the products
[HttpGet]
public ActionResult Index()
{
MainDbContext db = new MainDbContext();
var con = (from c in db.Products
select c).ToList();
return View(con);
}
//Update status of the products like active or inactive
[HttpPost]
public JsonResult UpdateStatus(int id, bool status)
{
MainDbContext db = new MainDbContext();
var result = db.Lists.Find(id);
if (result != null)
{
result.Status = status;
db.Entry(result).State = EntityState.Modified;
db.SaveChanges();
}
return Json(true);
}
查看:
@model SampleApp.Models.Product
@{
ViewBag.Title = "Index";
}
<link href="~/Scripts/jquery.btnswitch.css" rel="stylesheet" />
<script src="~/Scripts/jquery-3.1.1.slim.min.js"></script>
<script src="~/Scripts/jquery.btnswitch.js"></script>
<div id="divData">
<table class="table table-bordered table-condensed" id="data">
<thead>
<tr>
<th style="text-align:center;" class="hide">ID</th>
<th style="text-align:center;">Products</th>
<th style="text-align:center;">Time Posted</th>
<th style="text-align:center;">Status</th>
</tr>
</thead>
<tbody>
@for (int i = 0; i < Model.Items.Count; i++)
{
<tr>
<td id="ID" style="text-align: center;" class="hide">@Html.DisplayFor(modelItem => Model.Items[i].Id)</td>
<td style="text-align: center;">@Html.DisplayFor(modelItem => Model.Items[i].ProductName)</td>
<td style="text-align: center;">@Html.DisplayFor(modelItem => Model.Items[i].Time_Posted)</td>
<td style="text-align: center;">@Html.CheckBoxFor(modelItem => Model.Items[i].Status, new { @class = "toggle-checkbox", data_id = Model.Items[i].Id })</td>
</tr>
}
</tbody>
</table>
</div>
<script type="text/javascript">
var url = '@Url.Action("UpdateStatus")';
$('.toggle-checkbox').click(function () {
var isChecked = $(this).is(':checked'); //CheckBox checked - True or false
var id = $(this).data('id'); //Get the id of that specific checked row
$.post(url, { id: id, status: isChecked }, function (response) {
if (response) {
alert("Status changed");
}
})
});
</script>
<script>
$(document).ready(function () {
$('.toggle-checkbox').btnSwitch({ //This is the script for toggling
Theme: 'Light',
OnText: "On",
OffText: "Off",
OnValue: true,
OffValue: false
});
});
</script>
$('.toggle-checkbox').btnSwitch({
OnValue: 'On',
OnCallback: function(val) {
//your ajax code here
},
OffValue: 'Off',
OffCallback: function (val) {
//your ajax code here
}
});
使用此代码更改切换:
$('#toggle-checkbox').btnSwitch({
ToggleState:true //for switch on / true
});
$('#toggle-checkbox').btnSwitch({
ToggleState:false //for switch off / false
});
.switch {
position: relative;
display: inline-block;
width: 60px;
height: 34px;
}
.switch input {display:none;}
.slider {
position: absolute;
cursor: pointer;
top: 0;
left: 0;
right: 0;
bottom: 0;
background-color: #ccc;
-webkit-transition: .4s;
transition: .4s;
}
.slider:before {
position: absolute;
content: "";
height: 26px;
width: 26px;
left: 4px;
bottom: 4px;
background-color: white;
-webkit-transition: .4s;
transition: .4s;
}
input:checked + .slider {
background-color: #2196F3;
}
input:focus + .slider {
box-shadow: 0 0 1px #2196F3;
}
input:checked + .slider:before {
-webkit-transform: translateX(26px);
-ms-transform: translateX(26px);
transform: translateX(26px);
}
/* Rounded sliders */
.slider.round {
border-radius: 34px;
}
.slider.round:before {
border-radius: 50%;
}
<h2>Toggle Switch</h2>
<label class="switch">
<input type="checkbox">
<span class="slider"></span>
</label>
<label class="switch">
<input type="checkbox" checked>
<span class="slider"></span>
</label><br><br>
<label class="switch">
<input type="checkbox">
<span class="slider round"></span>
</label>
<label class="switch">
<input type="checkbox" checked>
<span class="slider round"></span>
</label>
试试这个。
您所需要的只是引导程序。下载任何 v5.x.x,这就是您所需要的。关键是 div 类中的 form-switch。应该可以吧
<div class="form-check form-switch">
<input class="form-check-input" type="checkbox" role="switch" id="flexSwitchCheckDefault">
<label class="form-check-label" for="flexSwitchCheckDefault">Default switch checkbox input</label>
</div>