通过 Post Android 将数据发送到 PHP

Question

所以，我正在尝试通过 Android 中的 Post 向 PHP 发送消息 这是 Android Java 函数：

 //enviando para o backend
private void SendtoPHP(String reg) throws IOException {


    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://bubbledev.com.br/gcm/getdevice.php");

    try{
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("regid", "" + reg ));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost);


    }
    catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }

}

PHP：

<?php       
include 'conecta.php';
$device_token  = urldecode($_POST['regid']);    
$sql = "INSERT INTO corposa.deviceandroid"
              . " (id,device_token)"
              . " VALUES (NULL,'$device_token')";
mysqli_query($con,$sql);    

？>

PHP 很好，我已经用另一篇文章测试了它并且可以工作，但是当 Android 函数尝试 $device_token 时没有收到任何值，并且 SQL 会在表中保存一个带有 id 的“”

Answer 1

我使用的代码与您的类似，除了 ResponseHandler 之外。 它对我有用。

HttpClient Client = new DefaultHttpClient();

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", sID));
nameValuePairs.add(new BasicNameValuePair("etc", sETC));

try {           

    String SetServerString = "";

    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://your-url.com/script.php");
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    ResponseHandler<String> responseHandler = new BasicResponseHandler();

    SetServerString = httpclient.execute(httppost, responseHandler);                

}  catch(Exception ex) {
    // failed
}

Answer 2

我确信有更好的方法可以做到这一点，但这就是我通常处理来自 Android 的 post 请求的方式：

<?php
{
    $input = json_encode(file_get_contents("php://input"));

    $deviceToken = $input->regId;
    mysqli_query($connection, "INSERT INTO corposa.deviceandroid (`id`, `device_token`) VALUES(NULL, '" . mysqli_real_escape_string($deviceToken) . "')";
}

此外，由于您使用的是 POST 而不是 GET，因此传递到服务器的数据没有进行 url 编码，因此这里不需要 urldecode。

Answer 3

代码看起来没问题，唯一“奇怪”的是：

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);

因为您只向列表中添加一个 BasicNameValuePair。也许这就是问题所在......？

Answer 4

我在当前的项目中使用此代码，希望它也适合您

  Map<String, String> kvPairs = new HashMap<String, String>();
    kvPairs.put("regid", reg);
    HttpClient httpclient = this.getNewHttpClient();
    HttpPost httppost = new HttpPost("http://bubbledev.com.br/gcm/getdevice.php");
    if (kvPairs != null && kvPairs.isEmpty() == false) {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(kvPairs.size());
        String k, v;
        Iterator<String> itKeys = kvPairs.keySet().iterator();
        while (itKeys.hasNext()) {
            k = itKeys.next();
            v = kvPairs.get(k);
            nameValuePairs.add(new BasicNameValuePair(k, v));
        }
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs, "UTF-8"));
    }
    HttpResponse response;
    response = httpclient.execute(httppost);
    String responseString = EntityUtils.toString(response.getEntity());

你的班级也需要这个方法

public static HttpClient getNewHttpClient() {
    try {
        KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
        trustStore.load(null, null);

        SSLSocketFactory sf = new RecorridoSSL(trustStore);
        sf.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);

        HttpParams params = new BasicHttpParams();
        HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
        HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);

        SchemeRegistry registry = new SchemeRegistry();
        registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
        registry.register(new Scheme("https", sf, 443));

        ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, registry);

        return new DefaultHttpClient(ccm, params);
    } catch (Exception e) {
        return new DefaultHttpClient();
    }
}

希望我没有忘记任何事情，有其他方式请告诉我

Answer 5

伙计们，错误出在我的 PHP 中

$device_token  = urldecode($_POST['regid']); 

这个 urldecode 搞乱了我的代码哈哈

感谢所有帮助

Answer 6

包 com.example.project_name

导入 android.os.Bundle

导入 android.widget.TextView 导入 androidx.appcompat.app.AppCompatActivity

导入com.android.volley.Response

导入com.android.volley.toolbox.StringRequest 导入 com.android.volley.toolbox.Volley

MainActivity 类：AppCompatActivity() {

override fun onCreate(savedInstanceState: Bundle?) {
    super.onCreate(savedInstanceState)
    setContentView(R.layout.activity_main)

    val textView = findViewById<TextView>(R.id.textView)
    val url = "https://path/index.php"

    val queue = Volley.newRequestQueue(this)

    val stringRequest = object : StringRequest(
        Method.POST, url,
        Response.Listener { response ->
            textView.text = response!! // Changed 'e' to 'd' for debug logging
        },
        Response.ErrorListener { error ->
            textView.text = error.toString()
        }) {
        override fun getParams(): Map<String, String> {
            val params = HashMap<String, String>() // Use HashMap instead of deprecated HasMap
            params["key1"] = "hello" // No duplicate key
            params["key2"] = "world" // Added second key-value pair

            return params
        }

// 重写 fun getHeaders(): Map { // return mapOf("Content-Type" to "application/x-www-form-urlencoded") // 更正了标头键的大小写 // } }

    queue.add(stringRequest)
}

}