如何在 SQL 子查询中获取计数

Question

我正在处理以下 SQL，我使用子查询获取一些值；我需要获得另一个值，但这有一些不同的条件：

SELECT Operator,
       COUNT(*) AS 'Sales',
       SUM(Commission) As 'Commission', 
       SUM(Fee + (2 * Commission)) As 'Amount',
       SUM(Prem) As 'Prem',
FROM (
    SELECT F.FormId,
           F.Prem,
           F.Agent,
           ((F.Prem/(1 + (112/100.00))) * ((PLS.Commission/100.00) * 50/100.00)) As 'Commission',
    CASE WHEN F.Prem!= PLPT.Charged THEN  ((F.Prem - PLPT.Charged) * (13.11/100.00)) 
         ELSE 0 
         END As 'Fee'
    FROM FORM F
    INNER JOIN PaymentTransaction PLPT ON F.FormId = PLPT.FormId
    INNER JOIN PublicScheme_backup PLS ON PLS.SchemeId = PLPT.SchemeId
    WHERE Agent IS NOT NULL 
    AND F.TranTypeId= 6
    AND Convert( date, F.Timestamp) BETWEEN '01 Jun 2024' AND '04 Jul 2024'
    AND F.FormId > 1950000 
) As X
GROUP BY Operator

以上查询操作员名称、销售数量、佣金、金额、预售费

Operator    Sales   Commission  Amount      Prem
--------------------------------------------------
8E          3       33.547300   94.640021   319.77

在此任务中需要获取记录计数，其中

TranTypeId = 7

将被标记为引号，但应基于每个运算符（按运算符分组）和给定的日期范围：

Operator    Sales   Commission  Amount      Prem    Quotes
------------------------------------------------------------------
8E          3       33.547300   94.640021   319.77  Expected value

我尝试过以下说法：

SELECT Operator,
        Count(*) AS 'Sales',
        SUM(Commission) AS 'Commission', 
        SUM(Fee + (2 * Commission)) AS 'Amount',
        SUM(Prem) AS 'Prem',
        (SELECT Count(*) 
         FROM Form 
         WHERE TranTypeId = 7 
              AND Convert(date,Datetimestamp)  BETWEEN '01 Jun 2024' AND '04 Jul 2024' 
              AND Operator = Operator
        ) AS 'Quotes'
FROM (
    SELECT F.FormId, 
           F.Prem,
           F.Agent,
           ((F.Prem/(1 + (112/100.00))) * ((PLS.Commission/100.00) * 50/100.00)) AS 'Commission',
           CASE WHEN F.Prem!= PLPT.Charged THEN  ((F.Prem - PLPT.Charged) * (13.11/100.00)) 
                ELSE 0 
                END AS 'Fee'
    FROM FORM F
    INNER JOIN PaymentTransaction PLPT ON F.FormId = PLPT.FormId
    INNER JOIN PublicScheme_backup PLS ON PLS.SchemeId = PLPT.SchemeId
    WHERE Agent IS NOT NULL 
          AND F.TranTypeId= 6
          AND Convert(date,F.Timestamp) BETWEEN '01 Jun 2024' AND '04 Jul 2024'
          AND F.FormId > 1950000 
) AS X
GROUP BY Operator

但我没有得到预期的结果 - 我为每个运算符得到相同的报价计数

Answer 1

谁能告诉我这是否正确

SELECT Operator,
            Count(*) AS 'Sales',
            SUM(Commission) AS 'Commission', 
            SUM(Fee + (2 * Commission)) AS 'Amount',
            SUM(Prem) AS 'Prem',
            (SELECT Count(*) FROM Form FS 
             WHERE TranTypeId = 7 AND FS.Operator = X.Operator
            ) AS 'Quotes'
    FROM (
        SELECT F.FormId, 
               F.Prem,
               F.Agent,
               ((F.Prem/(1 + (112/100.00))) * ((PLS.Commission/100.00) * 50/100.00)) AS 'Commission',
               CASE WHEN F.Prem!= PLPT.Charged THEN  ((F.Prem - PLPT.Charged) * (13.11/100.00)) 
                    ELSE 0 
                    END AS 'Fee'
        FROM FORM F
        INNER JOIN PaymentTransaction PLPT ON F.FormId = PLPT.FormId
        INNER JOIN PublicScheme_backup PLS ON PLS.SchemeId = PLPT.SchemeId
        WHERE Agent IS NOT NULL 
              AND F.TranTypeId= 6
              AND Convert(date,F.Timestamp) BETWEEN '01 Jun 2024' AND '04 Jul 2024'
              AND F.FormId > 1950000 
    ) AS X
    GROUP BY Operator

Answer 2

您可能需要使用条件聚合，如下所示：

SELECT Operator,
        Count(*) AS 'Sales',
        SUM(Commission) AS 'Commission', 
        SUM(Fee + (2 * Commission)) AS 'Amount',
        SUM(Prem) AS 'Prem',
        SUM(CASE WHEN TranTypeId = 7 THEN 1 ELSE 0 END) AS 'Quotes'
FROM (
    -- Your subquery
) AS X
GROUP BY Operator