从给定子字符串前缀和后缀的变量中删除所有出现的子字符串

Question

举个例子，我有一个变量包含：

sentence="\<Name\>Mary\</Name\> has a little lamb it's fleece as white as snow and everywhere that \<Name\>Sharon\</Name\> went the lamb was sure to go. \<Name\>Lucy\</Name\>, \<Name\>Mary\</Name\> quite contrary how does your garden grow?"

并且我需要删除（所有出现的）前缀

\<Name\>

和后缀

\</Name\>

之间的所有内容，包括前缀和后缀字符串本身以获得：

sentence=" has a little lamb it's fleece as white as snow and everywhere that  went the lamb was sure to go. ,  quite contrary how does your garden grow?"

我不知道如何实现这一目标。有人有 sed、awk 等解决方案吗？

Answer 1

最好的方法是使用 sed，如下所示：

#!/bin/bash
sentence="<Name>Mary</Name> has a little lamb it's fleece as white as snow and everywhere that <Name>Sharon</Name> went the lamb was sure to go. <Name>Lucy</Name>, <Name>Mary</Name> quite contrary how does your garden grow?"

# Use sed to remove everything between <Name> and </Name>, including the tags
cleaned_sentence=$(echo "$sentence" | sed 's/<Name>[^<]*<\/Name>//g')

echo "$cleaned_sentence"