def add_ranges(self):
self.ranges_layout = QtGui.QHBoxLayout() # setup the ranges_layout, it will be a child of all_ranges_layout
self.min_label = QtGui.QLabel(self.normalization) # setup the min label
self.max_label = QtGui.QLabel(self.normalization) # setup the max label
self.min_lineEdit = QtGui.QLineEdit(self.normalization) # setup the min lineEdit
self.max_lineEdit = QtGui.QLineEdit(self.normalization) # setup the max lineEdit
self.all_ranges_layout.addLayout(self.ranges_layout) # make ranges_layout a child of all_ranges_layout
self.ranges_layout.addWidget(self.min_label) # apply the min label to the widget
self.ranges_layout.addWidget(self.min_lineEdit) # apply the min lineEdit to the widget
self.ranges_layout.addWidget(self.max_label) # apply the max label
self.ranges_layout.addWidget(self.max_lineEdit) # apply the max lineEdit
self.min_label.setText(_translate("MainWindow", "Min", None)) # set the text of the min label
self.max_label.setText(_translate("MainWindow", "Max", None)) # set the text of the max label
self.min_lineEdits.append(self.min_lineEdit) # set up an array of lineEdits
self.max_lineEdits.append(self.max_lineEdit) #
def del_ranges(self):
self.ranges_layout.removeWidget(self.min_label) # remove the min label to the widget
self.ranges_layout.removeWidget(self.min_lineEdit) # remove the min lineEdit to the widget
self.ranges_layout.removeWidget(self.max_label) # remove the max label
self.ranges_layout.removeWidget(self.max_lineEdit) # remove the max lineEdit
del self.min_lineEdits[-1] # delete last element in list
del self.max_lineEdits[-1] # delete last element in list
单击“删除范围”,除了按钮在视觉上向上移动外,没有任何反应。这告诉我该功能正在工作(有点)并且正在删除布局,但不是 lineEdits 和标签。
这是我正在设计的程序中的两个功能。我想通过按一下按钮来添加和删除小部件。我尝试使用 deleteLater() 但是,这个函数也陷入了同一个坑;实际上并没有删除 lineEdits 和标签。是删除前没有断开连接的问题吗?
这是一种方法,可用于迭代遍历布局和
deleteLater()
特定布局中的每个小部件。在这种情况下self.all_ranges_layout
代码
def del_ranges(self):
to_delete = self.all_ranges_layout.takeAt(self.all_ranges_layout.count() - 1)
if to_delete is not None:
while to_delete.count():
item = to_delete.takeAt(0)
widget = item.widget()
if widget is not None:
widget.deleteLater()
else:
pass
简单的英语
get the layout item at n-1 index
if there are any objects to be deleted
while the count of objects is not 0
get the layout item at 0th index
get the widget at this location
if there is an object in this widget
deleteLater this widget