如何控制列表元素抛出键盘事件

Question

https://stackblitz.com/edit/react-o1ra7c

用户搜索结果后，用户尝试使用键盘事件箭头需要向下移动。

<div>
            
              
              <input onChange={handleSearchChange}/>
            
            <div css={countryDataCss}>
              {countryList?.map((country) => (
                <div key={country.countryCode}>
                  <span css={countryCss}>{country.countryName}</span>
                  <span css={countryDialCodeCss}>
                    {country.countryDialNo}
                  </span>
                </div>
              ))}
            </div>
          </div>

Answer 1

您可以使用 javascirpt 事件

onkeydown

，对于 React 来说是

onKeyDown

，它提供了所需的行为，请检查下面的 stackblitz！

import React from 'react';
import './style.css';
import { useState } from 'react';

export default function App() {
  const [searchText, setSearchText] = useState('');
  const [selectedCountry, setSelectedCountry] = useState('SG');
  const [activeIndex, setActiveIndex] = useState(0);
  const [selectedDialCode, setSelectedDialCode] = useState('+65');
  const countryCodeListResponse = [
    { countryCode: 'IND', countryDialNo: '+91', countryName: 'India' },
    { countryCode: 'SG', countryDialNo: '+65', countryName: 'Singpare' },
  ];
  const [countryList, setCountryList] = useState(countryCodeListResponse);
  function handleSearchChange(e) {
    const searchText = e.target.value.toLowerCase();

    if (countryCodeListResponse) {
      const updatedList = countryCodeListResponse
        .filter((el) => el.countryName.toLowerCase().includes(searchText))
        .sort(
          (a, b) =>
            a.countryName.toLowerCase().indexOf(searchText) -
            b.countryName.toLowerCase().indexOf(searchText)
        );

      setSearchText(searchText);
      setCountryList(updatedList);
    }
  }

  const onSelectCountry = (code, dialCode) => {
    setSelectedCountry(code);
    setSelectedDialCode(dialCode);
    setSearchText('');
    setCountryList(countryCodeListResponse);
  };

  const onKeyDown = (event) => {
    console.log(event);
    switch (event.keyCode) {
      case 38: // arrow up
        if (activeIndex > 0 && activeIndex <= countryList.length - 1) {
          setActiveIndex((prev) => prev - 1);
        }
        break;
      case 40: // arrow down
        if (activeIndex >= 0 && activeIndex < countryList.length - 1) {
          setActiveIndex((prev) => prev + 1);
        }
        break;
      case 13:
        const country = countryList[activeIndex];
        onSelectCountry(country.countryCode, country.countryDialNo);
        break;
      default:
        break;
    }
  };

  return (
    <div class="dropdown">
      <div class="search">
        <div>
          <span>{selectedCountry}</span>
          <span>{selectedDialCode}</span>
        </div>
        <input
          class="search-input"
          onKeyDown={(e) => onKeyDown(e)}
          placeholder="Search"
          value={searchText}
          onChange={handleSearchChange}
        />
      </div>
      <div class="list">
        {countryList?.map((country, index) => (
          <div
            onKeyDown={(e) => onKeyDown(e)}
            className={index === activeIndex ? 'active' : ''}
            tabIndex="0"
            key={country.countryCode}
            onClick={() =>
              onSelectCountry(country.countryCode, country.countryDialNo)
            }
          >
            <span>{country.countryName}</span>
            <span>{country.countryDialNo}</span>
          </div>
        ))}
      </div>
    </div>
  );
}

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