当我使用Bootstrap的模态时，我的Django表单不会渲染

Question

我在模式中渲染Django表单时遇到一些麻烦。我怀疑是因为我需要一些Ajax来获取浏览器中的url但我不知道如何。

形成：

class TrackedWebsitesForm(forms.ModelForm):
    class Meta:
        model = TrackedWebsites
        fields = "__all__"

视图：

def web(request):
    if request.method == 'POST':
        form = TrackedWebsitesForm(request.POST)
        if form.is_valid():
            try:
                form.save()
                return redirect('/websites')
            except:
                pass
    else:
        form = TrackedWebsitesForm()
    return render(request,'dashboard/create_website.html',{'form':form})

网址：

urlpatterns = [
    path('web', views.web),

create_website.html：

<div id="addEmployeeModal" class="modal fade">
  <div class="modal-dialog">
    <div class="modal-content">

<form method="POST" class="post-form" action="/web">
  {% csrf_token %}
  <div class="modal-header">
    <h4 class="modal-title">Add website</h4>
    <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
  </div>
  <div class="modal-body">
    <div class="form-group">
     {{ form.as_p }}
  </div>
  <div class="modal-footer">
    <input type="button" class="btn btn-default" data-dismiss="modal" value="Cancel">
    <input type="submit" class="btn btn-success" value="Add">
  </div>
</form>

</div>
</div>
</div>

一些照片

非工作模式形式：

通过链接直接访问时，表单有效：

有人可以帮帮我吗？我手动渲染表单字段，但我只是用form.as_p剪切它，否则问题将无法验证，因为代码太多了。

Answer 1

我认为如果你可以打开模态并且你没有可视化处方集，那是因为你没有加载它，试着这样做：

在views.py中添加它

def add_employee(request):
    form = TrackedWebsitesForm()
    return render(request, 'your_template', {'form':form})

在你的urls.py中添加它

path('employee/add', views.add_employee, name='add_employee'),

在你的HTML中

将其放在您打算打开模态的页面上，并将您的按钮包装在div中

 <div id="addEmployee">
    <a style="float:right" class="btn btn-success" >
        <i class="fas fa-fw fa-plus"></i> 
        <span>Add New Employee</span>
    </a>
</div>

<div id="addEmployeeModal" class="modal fade" role="dialog">
</div>

为模态创建不同的html并为表单添加id

<div class="modal-dialog">
    <div class="modal-content">
        <form id="addEmployeeForm" method="POST" class="post-form" action="/web">
            {% csrf_token %}
                <div class="modal-header">
                    <h4 class="modal-title">Add website</h4>
                    <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
                </div>
                <div class="modal-body">
                <div class="form-group">
                    {{ form.as_p }}
               </div>
               <div class="modal-footer">
                   <input type="button" class="btn btn-default" data-dismiss="modal" value="Cancel">
                   <input type="submit" class="btn btn-success" value="Add">
               </div>
        </form>
    </div>
</div>

在你的js

$(document).ready(function () {

    let my_modal = $("#addEmployeeModal");
    const url_form = "/employee/add";

    $("#addEmployee a").click(function () {
      my_modal.load(url_form, function () {
          my_modal.modal("show"); // Open Modal
          $("#addEmployeeForm").submit(function (e) {
              e.preventDefault(); // Cancel the default action
              $.ajax({
                  method: "POST",
                  data: $(this).serialize(),
                  dataType: "json",
                  url: "/url that handles the request/",
                  success: function (response) {
                      my_modal.modal('hide');
                  },
                  error: function (response) {

                  },});      
              });
          });
      });
  });

这个答案将带您到下一个问题，如何从模态发送数据后作出响应。因此，您必须在处理请求的视图中执行以下操作。

首先在views.py中导入以下内容

from django.http import JsonResponse

并在视图中处理请求复制此

if form.is_valid ():
    ...
    response = JsonResponse ({"message": 'success'})
    response.status_code = 201 // indicates that the request has been processed correctly
    return response
else:
    ...
    response = JsonResponse ({"errors": form.errors.as_json ()})
    response.status_code = 403 // indicates that there was an error processing the request
    return response