从aws lambda调用外部API并在lambda函数中以回调的形式获得重新放置

问题描述 投票:0回答:1

我正在尝试使用节点请求模块在aws Lambda函数内部调用外部API。到目前为止,我已经成功调用了API,并在lambda执行过程中获取了数据。我遇到的唯一问题是获取带有response.userinfo的userInfo数据。即使我的userInfo也有数据,在客户端给我空对象

var AWS = require('aws-sdk');
AWS.config.region = 'us-east-1';
var request = require('request');
const encode = require('nodejs-base64-encode');
var lambda = new AWS.Lambda();
import { Handler, Context, Callback } from "aws-lambda";
import { PayPalLinkDetails } from "../../View/PayPalLinkDetails";
import { PayPalLinkResponse, PayPalLinkResponseBody } from "../../View/PayPalLinkResponseBody";

const PAYPAL_CLIENT = process.env.PayPalClientID;
const PAYPAL_SECRET = process.env.PayPalSecretKEY;
const PAYPAL_OAUTH_API = process.env.PayPalAuthAPI;
const PAYPAL_IDENTITY_API = process.env.PayPalIdentityAPI;

const LinkPayPal: Handler = async (paypalRequest : PayPalLinkDetails, context: Context, callback: Callback) => {

    var userInfo = new PayPalLinkResponse();     
    var paypalresponse = new PayPalLinkResponseBody();
    const basicAuth = encode.encode(PAYPAL_CLIENT+":"+PAYPAL_SECRET, 'base64');      
      var options = {
        'method': 'POST',
        'url': PAYPAL_OAUTH_API,
        'headers': {
          'Authorization': 'Basic '+basicAuth,
          'Content-Type': 'application/x-www-form-urlencoded'
        },
        form: {
          'grant_type': 'authorization_code',
          'code': paypalRequest.code
        }
      };

      await request(options, async function (error : any, response :any) { 
        if (error)
        {
           console.log(error);
        }
        else
        {
            paypalresponse = response.body;
           // save data to DB here
        }

      });

      var getIdentity = {'method': 'get','url': PAYPAL_IDENTITY_API,'headers': {'Authorization': 'Basic '+basicAuth,'Content-Type': 'application/x-www-form-urlencoded'},form: {'grant_type': 'authorization_code','code': paypalresponse.access_token}};

       await request(getIdentity, function (err : any, res :any)
                                {
                                    if (err)
                                    {
                                        console.log(err);
                                    }
                                    else
                                    {        
                                        userInfo = res.body; // this Print the values as expected
                                        console.log(userInfo);

                                    }
                                });


 callback(null,userInfo); // This Giving me Empty value      
}

export {LinkPayPal}  

我认为我以错误的方式调用了回调。有什么建议可以解决这个问题..?

node.js aws-lambda http-post nodejs-server
1个回答
1
投票

问题是,您混合使用了回调和异步/等待样式,这无法按预期的方式工作。您在这里有几个选择

  • [[不推荐]:执行嵌套回调,并在第一个回调的响应上,调用第二个请求,依此类推。

  • [[不推荐]:使用请求包的承诺版本,称为request-promise,因为现在正在使用它。

  • [[不推荐]:通过包装在Promise中,将请求的回调样式转换为Promise。再次取消使用request模块。有关更多详细信息,请参见here

  • [[Recommended]:使用一些现成的软件包,这些软件包开箱即用地支持Promise,并且正确维护。像gotaxios等。您可以看到列表here

如果您使用got pacakge进行http调用,代码将是这样。

var AWS = require("aws-sdk");
AWS.config.region = "us-east-1";
var got = require("got");
const encode = require("nodejs-base64-encode");
var lambda = new AWS.Lambda();
import { Handler, Context, Callback } from "aws-lambda";
import { PayPalLinkDetails } from "../../View/PayPalLinkDetails";
import {
  PayPalLinkResponse,
  PayPalLinkResponseBody
} from "../../View/PayPalLinkResponseBody";

const PAYPAL_CLIENT = process.env.PayPalClientID;
const PAYPAL_SECRET = process.env.PayPalSecretKEY;
const PAYPAL_OAUTH_API = process.env.PayPalAuthAPI;
const PAYPAL_IDENTITY_API = process.env.PayPalIdentityAPI;

const LinkPayPal: Handler = async (
  paypalRequest: PayPalLinkDetails,
  context: Context,
  callback: Callback
) => {
  var userInfo = new PayPalLinkResponse();
  var paypalresponse = new PayPalLinkResponseBody();
  const basicAuth = encode.encode(
    PAYPAL_CLIENT + ":" + PAYPAL_SECRET,
    "base64"
  );
  var options = {
    method: "POST",
    url: PAYPAL_OAUTH_API,
    headers: {
      Authorization: "Basic " + basicAuth,
      "Content-Type": "application/x-www-form-urlencoded"
    },
    form: {
      grant_type: "authorization_code",
      code: paypalRequest.code
    }
  };

  const paypalresponse = await got(options);

  var getIdentity = {
    method: "get",
    url: PAYPAL_IDENTITY_API,
    headers: {
      Authorization: "Basic " + basicAuth,
      "Content-Type": "application/x-www-form-urlencoded"
    },
    form: {
      grant_type: "authorization_code",
      code: paypalresponse.access_token
    }
  };

  const userInfo = await got(getIdentity);

  return userInfo;
};

export { LinkPayPal };

您可能需要根据got样式调整选项,但您会有所了解。

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