我有一个QGridLayout,我要在其中添加不同的元素,我需要知道这些元素,并且需要知道特定元素的坐标。有办法吗?我阅读了文档,并尝试使用pos()和geometry()属性,但无法获得所需的内容。例如,给出以下代码:
import sys
from PyQt5.QtWidgets import (QWidget, QGridLayout,QPushButton, QApplication)
class basicWindow(QWidget):
def __init__(self):
super().__init__()
grid_layout = QGridLayout()
self.setLayout(grid_layout)
for x in range(3):
for y in range(3):
button = QPushButton(str(str(3*x+y)))
grid_layout.addWidget(button, x, y)
self.setWindowTitle('Basic Grid Layout')
if __name__ == '__main__':
app = QApplication(sys.argv)
windowExample = basicWindow()
windowExample.show()
sys.exit(app.exec_())
是否可以了解每个按钮的坐标?
仅在显示小部件时才会更新几何,因此您可能在显示坐标之前先打印坐标。在以下示例中,如果按任意按钮,它将打印相对于窗口的坐标。
import sys
from PyQt5.QtCore import pyqtSlot
from PyQt5.QtWidgets import QWidget, QGridLayout, QPushButton, QApplication
class BasicWindow(QWidget):
def __init__(self):
super().__init__()
grid_layout = QGridLayout(self)
for x in range(3):
for y in range(3):
button = QPushButton(str(3 * x + y))
button.clicked.connect(self.on_clicked)
grid_layout.addWidget(button, x, y)
self.setWindowTitle("Basic Grid Layout")
@pyqtSlot()
def on_clicked(self):
button = self.sender()
print(button.text(), ":", button.pos(), button.geometry())
if __name__ == "__main__":
app = QApplication(sys.argv)
windowExample = BasicWindow()
windowExample.show()
sys.exit(app.exec_())
输出:
0 : PyQt5.QtCore.QPoint(10, 10) PyQt5.QtCore.QRect(10, 10, 84, 34)
4 : PyQt5.QtCore.QPoint(100, 50) PyQt5.QtCore.QRect(100, 50, 84, 34)
8 : PyQt5.QtCore.QPoint(190, 90) PyQt5.QtCore.QRect(190, 90, 84, 34)