如何通过Paramiko获取目录中所有SFTP文件的大小

Question

import paramiko
from socket import error as socket_error
import os 
server =['10.10.0.1','10.10.0.2']
path='/home/test/'
for hostname in server:
    try:
        ssh_remote =paramiko.SSHClient()
        ssh_remote.set_missing_host_key_policy(paramiko.AutoAddPolicy())
        privatekeyfile = os.path.expanduser('~/.ssh/id')
        mykey = paramiko.RSAKey.from_private_key_file(privatekeyfile, password='test123')
        ssh_remote.connect(hostname, username = 'test1', pkey = mykey)
        sftp=ssh_remote.open_sftp()
        for i in sftp.listdir(path):
            info = sftp.stat(i)
            print info.st_size      
    except paramiko.SSHException as sshException:
        print "Unable to establish SSH connection:{0}".format(hostname)
    except socket_error as socket_err:
        print "Unable to connect connection refused"

这是我的代码。我试图获取远程服务器文件的文件大小。但是下面的错误就是投掷。有人可以指导一下吗？

错误

Traceback (most recent call last):
  File "<stdin>", line 15, in <module>
  File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 337, in stat
    t, msg = self._request(CMD_STAT, path)
  File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 624, in _request
    return self._read_response(num)
  File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 671, in _read_response
    self._convert_status(msg)
  File "/usr/lib/python2.6/site-packages/paramiko/sftp_client.py", line 697, in _convert_status
    raise IOError(errno.ENOENT, text)
IOError: [Errno 2] No such file

Answer 1

SFTPClient.listdir仅返回文件名，而不是完整路径。因此，要在另一个API中使用文件名，您必须添加一个路径：

for i in sftp.listdir(path):
    info = sftp.stat(path + "/" + i)
    print info.st_size     

---

虽然那效率很低。 Paramiko已经知道了这个尺寸，你只是通过使用SFTPClient.listdir而不是SFTPClient.listdir_attr（listdir在内部调用listdir_attr）来抛弃信息。

for i in sftp.listdir_attr(path):
    print i.st_size