Jasmine SpyObj不返回模拟对象

问题描述 投票:2回答:1

我正在尝试测试以下服务。

@Injectable()
export class TranslationService {

  language = 'NL';

  constructor(contextService: ContextService) {
    let context = contextService.getContext();
    this.language = context.language;
  }
}

实际测试:

describe('TranslationService', () => {

  let service: TranslationService;
  let contextServiceSpy: jasmine.SpyObj<ContextService>;

  beforeEach(() => {

    const contextSpy = jasmine.createSpyObj('ContextService', ['getContext']);
 
    TestBed.configureTestingModule({
      providers: [
        TranslationService,
        {provide: ContextService, useValue: contextSpy}]
    });

    service = TestBed.get(TranslationService);
    contextServiceSpy = TestBed.get(ContextService);
  
  });

  it('should create an instance', () => {

    const context: Context = {
      language: 'EN'
    };

    contextServiceSpy.getContext.and.returnValue(context);

    expect(service).toBeDefined();
    expect(contextServiceSpy.getContext.calls.count()).toBe(1, 'spy method was called once');
    expect(contextServiceSpy.getContext.calls.mostRecent().returnValue).toBe(context);
  });

});

现在运行我的测试时它会返回一个错误:

TypeError: Cannot read property 'language' of undefined

这意味着间谍没有返回我的模拟上下文。但我不知道为什么不是。任何人?

我用过https://angular.io/guide/testing#service-tests

角度5.2.4

茉莉花2.8.0

javascript angular jasmine2.0
1个回答
2
投票

在模拟getContext存根之前调用服务构造函数。

它应该是:

contextServiceSpy = TestBed.get(ContextService);
contextServiceSpy.getContext.and.returnValue(context);
service = TestBed.get(TranslationService);
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