Python Json从文本文件创建字典，打印文件问题

Question

我能够获取一个文本文件，阅读每一行，每行创建一个字典，更新（附加）每一行并存储json文件。问题是，当读取json文件时，它将无法正确读取。错误指向存储文件问题？

文本文件看起来像：

84.txt;科学怪人，或现代普罗米修斯；玛丽·沃斯通克拉夫特（戈德温）雪莱98.txt;双城记;查尔斯·狄更斯...

import json
import re

path = "C:\\...\\data\\"

books = {}
books_json = {}
final_book_json ={}

file = open(path + 'books\\set_of_books.txt', 'r') 
json_list = file.readlines()
open(path + 'books\\books_json.json', 'w').close() # used to clean each test

json_create = []
i = 0

for line in json_list:
    line = line.replace('#', '')
    line = line.replace('.txt','')
    line = line.replace('\n','')
    line = line.split(';', 4)
    BookNumber = line[0]
    BookTitle = line[1]
    AuthorName = line[-1]
file
    if BookNumber == ' 2701': 
        BookNumber = line[0]
        BookTitle1 = line[1]
        BookTitle2 = line[2]
        AuthorName = line[3]
        BookTitle = BookTitle1 + ';' + BookTitle2 # needed to combine title into one to fit dict format
    books = json.dumps( {'AuthorName': AuthorName,  'BookNumber': BookNumber, 'BookTitle': BookTitle})
    books_json = json.loads(books)
    final_book_json.update(books_json)
    with open(path + 'books\\books_json.json', 'a'
             ) as out_put:                 
        json.dump(books_json, out_put)

with open(path + 'books\\books_json.json', 'r'
         ) as out_put:
'books\\books_json.json', 'r')]
    print(json.load(out_put))  

报告的错误是：JSONDecodeError：额外的数据：第1行第133列（字符132）-将其添加在第一个“} {”之间。不确定json应该以平面文件格式显示吗？输出文件如上所示编辑器看起来像：{“ AuthorName”：“ Mary Wollstonecraft（Godwin）Shelley”，“ BookNumber”：“ 84”，“ BookTitle”：“ Frankenstein或现代普罗米修斯”} {“ AuthorName”：“ Charles Dickens”，“ BookNumber”：“98“，” BookTitle“：”两个城市的故事“} ...

Answer 1

我最终改变了方法，并使用熊猫来读取文本，然后拆分单单元格输入。

    books = pd.read_csv(path + 'books\\set_of_books.txt', sep='\t', names =('r','t', 'a') )
    #print(books.head(10))

    # Function to clean the 'raw(r)' inoput data 
    def clean_line(cell):
...
        return cell

    books['r'] = books['r'].apply(clean_line)
    books = books['r'].str.split(';', expand=True)