如何使用Selenium和Python在https://tinder.com/中找到Facebook登录按钮

Question

[每次我加载python脚本时，每次登录前都要手动更改Facebook登录按钮和弹出按钮的Xpath。如何更改此设置，这样我就不必手动输入XPath？

from selenium import webdriver
from time import sleep

class TinderBot():
    def __init__(self):
        self.driver = webdriver.Chrome()

    def login(self):
        self.driver.get('https://tinder.com')

        sleep(3)

        #fbxpath = //button[@type = 'button' and @aria-label = 'Log in with Facebook']

        fb_btn = self.driver.find_element_by_xpath('//*[@id="content"]/div/div[1]/div/div/main/div/div[2]/div[2]/div/div/span/div[2]/button')
        fb_btn.click()

        base_window = self.driver.window_handles[0]
        self.driver.switch_to_window(self.driver.window_handles[1])
        fbemail = self.driver.find_element_by_xpath('//*[@id="email"]')
        fbemail.send_keys('[email protected]')

        fbpass = self.driver.find_element_by_xpath('//*[@id="pass"]')
        fbpass.send_keys('BlackToast5')

        login_btn = self.driver.find_element_by_xpath('//*[@id="u_0_0"]')
        login_btn.click()

        self.driver.switch_to_window(base_window)

        popup1 = self.driver.find_element_by_xpath('//*[@id="modal-manager"]/div/div/div/div/div[3]/button[1]')
        popup1.click()

        popup2 = self.driver.find_element_by_xpath('//*[@id="modal-manager"]/div/div/div/div/div[3]/button[1]')
        popup2.click()

bot = TinderBot()
bot.login()

这是我得到的错误：

File "tind_bt.py", line 16, in login
    fb_btn = self.driver.find_element_by_xpath('//*[@id="content"]/div/div[1]/div/div/main/div/div[2]/div[2]/div/div/span/div[2]/button')
  File "C:\ProgramData\Anaconda3\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 394, in find_element_by_xpath
    return self.find_element(by=By.XPATH, value=xpath)
  File "C:\ProgramData\Anaconda3\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 978, in find_element
    'value': value})['value']
  File "C:\ProgramData\Anaconda3\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
    self.error_handler.check_response(response)
  File "C:\ProgramData\Anaconda3\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id="content"]/div/div[1]/div/div/main/div/div[2]/div[2]/div/div/span/div[2]/button"}
  (Session info: chrome=80.0.3987.106)

Answer 1

你很近。要在文本为使用Facebook登录的元素上调用click()，您需要诱导WebDriverWait，直到element_to_be_clickable()到达子级<span>，并且可以使用以下任一[C0 ]：

• 使用Locator Strategies：

  CSS_SELECTOR

• 使用WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[type = 'button'][aria-label = 'Log in with Facebook'] span"))).click() ：

  XPATH

• 注：您必须添加以下导入：

  WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[@type = 'button' and @aria-label = 'Log in with Facebook']//span"))).click()
  

• 浏览器快照：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Answer 2

也许您可以实现WebDriverWait，看看是否可以解决问题。

这可能会让您入门-

这是显式等待的Python文档-Selenium WebDriver wait till element is displayed