正则表达式需要一个url模式

Question

我正在添加一些简单的路由而不使用任何特定的框架。

当前的正则表达式 - >

/^(\w)\/?(\w)\/?(\w)\/?(\d+)$/g

可能的url模式是

settings                                // should be matched to --> group1 = settings, group2 = null, group3 = null, group4 = null
settings/                               // should be matched to --> group1 = settings, group2 = null, group3 = null, group4 = null
settings/205                            // should be matched to --> group1 = settings, group2 = null, group3 = null, group4 = 205

settings/notifications                  // should be matched to --> group1 = settings, group2 = notifications, group3 = null, group4 = null
settings/notifications/                 // should be matched to --> group1 = settings, group2 = notifications, group3 = null, group4 = null
settings/notifications/50               // should be matched to --> group1 = settings, group2 = notifications, group3 = null, group4 = 50

settings/notifications/pingers          // should be matched to --> group1 = settings, group2 = notifications, group3 = pingers, group4 = null
settings/notifications/pingers/         // should be matched to --> group1 = settings, group2 = notifications, group3 = pingers, group4 = null
settings/notifications/pingers/101      // should be matched to --> group1 = settings, group2 = notifications, group3 = pingers, group4 = 101

非常感谢帮助！

Answer 1

您可以在string#split上/并测试最后一个单词是否为数字和空字符串并使用解构创建您的对象。

var arr = ['settings', 'settings/','settings/205','settings/notifications','settings/notifications/', 'settings/notifications/50','settings/notifications/pingers','settings/notifications/pingers/','settings/notifications/pingers/101']

var result = arr.map(url => {
  var words = url.split('/');
  var last = null;
  
  if(/\d+/g.test(words[words.length - 1]))
      last = words.pop();
  else if(!words[words.length - 1] || /\s+/g.test(words[words.length - 1]))
    words.pop();
  
  var [group1, group2=null, group3=null] = [...words];
  var group4 = last;
  return {group1, group2, group3, group4};
});

console.log(result);

Answer 2

请在perl中尝试以下代码。模式本身无处不在。

$string  = "settings/notifications/pingers/101";
#$string  = "settings/notifications/pingers";
#$string  = "settings/notifications";
#$string  = "settings";

$string  =~  m/^(\w+)(?:\/)?(\w+)?(?:\/)?(\w+)?(?:\/)?(\d+)?$/;

print $1."\n"; 
print $2."\n"; 
print $3."\n"; 
print $4."\n";