如何使用Python中的属性在两个带有参数的方法之间进行动态选择

Question

我有一个 Python 类，需要根据条件在两种方法之间动态选择。两种方法都带有参数。我想使用一个属性来确定要调用哪个方法。我怎样才能实现这个目标？

class MyClass:
    def __init__(self, condition):
        self.condition = condition

    def _method_1(self, param1, param2):
        # Implementation for the first add_way method
        print(f"_method_1 called with {param1} and {param2}")

    def _method_2(self, param1, param2):
        # Implementation for the second add_way method
        print(f"_method_2 called with {param1} and {param2}")

    @property
    def method(self):
        # How to return the correct method based on self.condition?
        pass

# Example usage:
manager = WayManager(condition=True)
manager.method('value1', 'value2')  # Should call _method_1 with 'value1' and 'value2'

manager.condition = False
manager.method('value3', 'value4')  # Should call _method_2 with 'value3' and 'value4'

如何实现方法属性来实现此行为？

Answer 1

只需从您的

method

属性返回正确的方法即可。 （它会自动绑定到同一个

self

实例，所以你不需要担心类似的事情。）

class MyClass:
    def __init__(self, condition):
        self.condition = condition

    def _method_1(self, param1, param2):
        print(f"{self}._method_1 called with {param1=} and {param2=}")

    def _method_2(self, param1, param2):
        print(f"{self}._method_2 called with {param1=} and {param2=}")

    @property
    def method(self):
        return self._method_1 if self.condition else self._method_2


manager = MyClass(condition=True)
manager.method("value1", "value2")
manager.condition = False
manager.method("value3", "value4")

打印出来

<__main__.MyClass object at 0x1031c91f0>._method_1 called with param1='value1' and param2='value2'
<__main__.MyClass object at 0x1031c91f0>._method_2 called with param1='value3' and param2='value4'