使用带有Python assertRaises的上下文管理器

Question

unittest的Python文档暗示assertRaises()方法可以用作上下文管理器。下面的代码给出了一个Python文档中单元测试的简单示例。在assertRaises()方法中的testsample()调用工作正常。

现在我想在引发异常时访问异常，但是如果我将它注释掉，而是取消注释我尝试使用上下文管理器的下一个块，当我尝试执行代码时，我得到一个AttributeError: __exit__。这适用于Python 2.7.2和3.2.2。我可以在try...except块中捕获异常并以这种方式访问​​它，但unittest的文档似乎暗示上下文管理器也会这样做。

还有别的我在这里做错了吗？

class TestSequenceFunctions(unittest.TestCase):

    def setUp(self):
        self.seq = [x for x in range(10)]

    def testshuffle(self):
        # make sure the shuffled sequence does not lose any elements
        random.shuffle(self.seq)
        self.seq.sort()
        self.assertEqual(self.seq, [x for x in range(10)])

    def testchoice(self):
        element = random.choice(self.seq)
        self.assert_(element in self.seq)

    def testsample(self):
        self.assertRaises(ValueError, random.sample, self.seq, 20)

        # with self.assertRaises(ValueError, random.sample, self.seq, 20):
        #     print("Inside cm")

        for element in random.sample(self.seq, 5):
            self.assert_(element in self.seq)

if __name__ == '__main__':
    unittest.main()

Answer 1

source code for unittest没有显示assertRaises的异常钩子：

class _AssertRaisesContext(object):
    """A context manager used to implement TestCase.assertRaises* methods."""

    def __init__(self, expected, test_case, expected_regexp=None):
        self.expected = expected
        self.failureException = test_case.failureException
        self.expected_regexp = expected_regexp

    def __enter__(self):
        return self

    def __exit__(self, exc_type, exc_value, tb):
        if exc_type is None:
            try:
                exc_name = self.expected.__name__
            except AttributeError:
                exc_name = str(self.expected)
            raise self.failureException(
                "{0} not raised".format(exc_name))
        if not issubclass(exc_type, self.expected):
            # let unexpected exceptions pass through
            return False
        self.exception = exc_value # store for later retrieval
        if self.expected_regexp is None:
            return True

        expected_regexp = self.expected_regexp
        if isinstance(expected_regexp, basestring):
            expected_regexp = re.compile(expected_regexp)
        if not expected_regexp.search(str(exc_value)):
            raise self.failureException('"%s" does not match "%s"' %
                     (expected_regexp.pattern, str(exc_value)))
        return True

因此，正如您所怀疑的那样，如果您想要在保持assertRaises测试的同时拦截异常，那么构建您自己的try / except块是可行的方法：

def testsample(self):
    with self.assertRaises(ValueError):
         try:
             random.sample(self.seq, 20)
         except ValueError as e:
             # do some action with e
             self.assertEqual(e.args,
                              ('sample larger than population',))
             # now let the context manager do its work
             raise                    

Answer 2

似乎没有人提出：

import unittest
# For python < 2.7, do import unittest2 as unittest

class Class(object):
    def should_raise(self):
        raise ValueError('expected arg')

class test_Class(unittest.TestCase):
    def test_something(self):
        DUT = Class()
        with self.assertRaises(ValueError) as exception_context_manager:
            DUT.should_raise()
        exception = exception_context_manager.exception

        self.assertEqual(exception.args, ('expected arg', ))

我通常使用e_cm作为exception_context_manager的缩写。

Answer 3

根据文件：

如果使用省略的callableObj或None调用，则返回上下文对象

所以代码应该是：

with self.assertRaises(ValueError):
    random.sample(self.seq, 20)

Answer 4

考虑到这是六年前的问题，我想这是现​​在有效但当时没有用的东西。 docs国家出现在2.7但不是微型版本。

import unittest

class TestIntParser(unittest.TestCase):

    def test_failure(self):
        failure_message = 'invalid literal for int() with base 10'
        with self.assertRaises(ValueError) as cm:
            int('forty two')
        self.assertIn(failure_message, cm.exception.message)

if __name__ == '__main__':
    unittest.main()