我的Spring Boot应用程序的所有端点都希望有2个查询参数(http://localhost:myapplcation/getAll?pid=1101&token=jdu191092kj11
),所有端点都按预期工作。但是,如果我传递2个查询参数,我就能看到api swagger(http://localhost:8080/v2/api-docs?pid=1101&token=jdu191092kj11
)
此Swagger UI的问题..没有显示http://localhost:8080/swagger-ui.html
我该如何解决?
下面是代码:
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurationSupport;
import springfox.documentation.builders.ApiInfoBuilder;
import springfox.documentation.builders.RequestHandlerSelectors;
import springfox.documentation.service.ApiInfo;
import springfox.documentation.service.Contact;
import springfox.documentation.spi.DocumentationType;
import springfox.documentation.spring.web.plugins.Docket;
import springfox.documentation.swagger2.annotations.EnableSwagger2;
import static springfox.documentation.builders.PathSelectors.regex;
@Configuration
@EnableSwagger2
public class SwaggerConfig extends WebMvcConfigurationSupport {
@Bean
public Docket productApi() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("com.springframework.controllers"))
.paths(regex("/product.*"))
.build()
.apiInfo(metaData());
}
private ApiInfo metaData() {
return new ApiInfoBuilder()
.title("Spring Boot REST API")
.description("\"Spring Boot REST API for Online Store\"")
.version("1.0.0")
.license("Apache License Version 2.0")
.licenseUrl("https://www.apache.org/licenses/LICENSE-2.0\"")
.contact(new Contact("John Thompson", "https://springframework.com", "john@springfrmework.com"))
.build();
}
@Override
protected void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("swagger-ui.html")
.addResourceLocations("classpath:/META-INF/resources/");
registry.addResourceHandler("/webjars/**")
.addResourceLocations("classpath:/META-INF/resources/webjars/");
}
}
在正则表达式中,您要添加产品。*,但在url路径中您没有产品字词。
让我们简单点,看看它是否像下面那样工作
@Bean
public Docket api() {
return new Docket(DocumentationType.SWAGGER_2)
.apiInfo(metaData())
.apis(RequestHandlerSelectors.withClassAnnotation(RestController.class))
.paths(PathSelectors.any())
.build();
}