如何在Symfony 4中配置http_basic防火墙，使其在认证失败时返回JSON响应体？

Question

默认情况下，当你在Symfony中配置http_basic防火墙时，防火墙会返回 "401 Unauthorized "和一个无效凭证请求的空体。

我想让它返回一个自定义的JSON(例如: {'errorCode' => 'AUTHORIZATION_FAILURE', 'errorMessage' => 'The provided credentials are not valid'}). 这可能吗？

我的 onAuthenticationFailure 方法不返回我的自定义响应。它返回默认的响应。

我的AuthenticationListener类，将订阅这些事件。

<?php
namespace App\EventListener;

use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Security\Core\Event\AuthenticationFailureEvent;
use Symfony\Component\Security\Http\Event\InteractiveLoginEvent;

class AuthenticationListener
{   
    public function onAuthenticationFailure(AuthenticationFailureEvent $event)
    {
        //executes on failed login
        $content = array('errorCode' => 'AUTHORIZATION_FAILURE', 'errorMessage' => 'The provided credentials are not valid');
        // dd(json_encode($content));

        //the bellow code is not working
        $response = new Response();
        $response->headers->set('Content-Type', 'application/json');
        $response->setContent(json_encode($content))
                ->setStatusCode(200);

        return $response;
    }
}
?>

我的安全YAML

firewalls:
        api:
            pattern: ^/1
            anonymous: false
            provider: in_api
            http_basic: ~

我的服务 YAML

# authentication failure event listener
    acme.security.authentication_failure_event_listener:
        class: App\EventListener\AuthenticationListener
        arguments: [ api ]
        tags:
            - { name: kernel.event_listener, priority: 100, event: security.authentication.failure, method: onAuthenticationFailure }

Answer 1

当我使用 header('Content-Type: application/json');echo json_encode($content);exit; 它返回预期的结果。