VS Code 中不存在的 & 符号出现语法错误

Question

当我从 VS Code 内部运行代码时，出现此错误。据我了解，它警告我关于我的代码中不存在的

&

符号，或者它是其他东西？：

& C:/Users/iwanh/AppData/Local/Programs/Python/Python310/python.exe "c:/Users/iwanh/AppData/Local/Programs/Giannis' Programs/bbc_news.py"
  File "<stdin>", line 1
    & C:/Users/iwanh/AppData/Local/Programs/Python/Python310/python.exe"c:/Users/iwanh/AppData/Local/Programs/Giannis' Programs/bbc_news.py" 
    ^
SyntaxError: invalid syntax

但是如果我使用

python.exe bbc_news.py

从 cmd 运行 .py 文件，它会按预期运行。当前运行Python 3.10.8。 VS Code 使用相同版本。

仅供参考，这是我的代码：

import requests
from bs4 import BeautifulSoup
import pandas as pd

def scrape_bbc_news(url):
    try:
        # Send a GET request to the URL
        response = requests.get(url)
        response.raise_for_status()  # Raise an exception for bad response status
        
        # Parse the HTML content
        soup = BeautifulSoup(response.content, 'html.parser')
        
        # Initialize lists to store headlines, descriptions, and links
        headlines = []
        descriptions = []
        links = []
        
        # Find all containers that hold both headline, description, and link
        article_containers = []
        
        # First type of container
        containers_type1 = soup.find_all('div', class_='sc-f98732b0-3 ephYtw')
        article_containers.extend(containers_type1)
        
    
        
        for container in article_containers:
            # Check if the article contains a "live" icon
            live_icon = container.find('svg', class_='sc-3387039d-0 hgdstu sc-1097f7fe-0 jmthjj')
            if live_icon:
                continue  # Skip this article if it contains a live icon
            
            # Extract headline
            headline = container.find('h2', class_='sc-4fedabc7-3 dsoipF').text.strip()
            headlines.append(headline)
            
            # Extract description
            description = container.find('p', class_='sc-f98732b0-0 iQbkqW').text.strip()
            descriptions.append(description)
            
            # Extract link
            link = container.find('a', class_='sc-2e6baa30-0 gILusN')['href'] if container.find('a', class_='gs-c-promo-heading') else ''
            links.append(link)
        
        # Check if lengths of headlines, descriptions, and links match
        if len(headlines) != len(descriptions) or len(headlines) != len(links):
            raise ValueError("Number of headlines, descriptions, and links do not match")
        
        # Create a DataFrame from the extracted data
        df = pd.DataFrame({
            'headline': headlines,
            'description': descriptions,
            'link': links
        })
        
        return df
        
    except requests.exceptions.RequestException as e:
        print(f"Error fetching data: {e}")
        return None
    except ValueError as ve:
        print(f"ValueError: {ve}")
        return None

# Example usage:
url = "https://www.bbc.com/news"
df = scrape_bbc_news(url)

if df is not None:
    print("Headlines, descriptions, and links scraped successfully:")
    print(df.head())
    df.to_csv('bbc_news_headlines.csv', index=False, encoding='utf-8')
    print("Data saved to 'bbc_news_headlines.csv' successfully.")
else:
    print("Failed to scrape data.")

Answer 1

您看到的错误消息是 Python 错误消息，该命令应该在 Powershell 中执行。

如果您手动输入命令，则应在终端窗口中执行此操作，确保当前提示符以

PS 

(Powershell) 开头。

使用播放按钮（右上角）运行代码应该会打开一个 Powershell 会话来运行该命令。