我是java新手,我只是想显示一条错误消息,如果用户从键盘点击转义键或点击showInputDialog
的X按钮或按取消,程序正常关闭,
就像现在如果我关闭或取消inputDialog它会给出以下错误
Exception in thread "main" java.lang.NullPointerException at Main.main(Main.java:11)
我也尝试抛出异常JVM,但它不能像我预期的那样工作,这是我的代码:
String userInput;
BankAccount myAccount = new BankAccount();
while (true){
userInput = JOptionPane.showInputDialog("1. Withdraw\n2. Deposit\n3. View Balance\n4. Exit");
switch (userInput){
case "1":
myAccount.withdraw(Integer.parseInt(JOptionPane.showInputDialog("Please Enter ID: ")),Double.parseDouble(JOptionPane.showInputDialog("Please Enter Amount to Withdraw: ")));
break;
case "2":
myAccount.deposit(Integer.parseInt(JOptionPane.showInputDialog("Please Enter ID: ")),Double.parseDouble(JOptionPane.showInputDialog("Please enter Amount to Deposit: ")));
break;
case "3":
myAccount.viewBalance(Integer.parseInt(JOptionPane.showInputDialog("Please Enter ID: ")));
break;
case "4":
myAccount.exit();
System.exit(0);
default:
JOptionPane.showMessageDialog(null,"Invalid Input\nPlease Try Again");
break;
}
}
我只想在用户单击X或取消提示时显示错误消息,我该如何捕获?所以我会在那里实现我的逻辑
如果用户单击“x”或“取消”按钮,JOptionPane.showInputDialog将返回null,而不是字符串。所以代替:
while (true){
userInput = JOptionPane.showInputDialog("1. Withdraw\n2. Deposit\n3. View Balance\n4. Exit");
switch (userInput){
case "1": ...
您可能想要做类似的事情:
while (true){
userInput = JOptionPane.showInputDialog("1. Withdraw\n2. Deposit\n3. View Balance\n4. Exit");
if (userInput == null) {
JOptionPane.showMessageDialog(null, "Invalid Input\nPlease Try Again", "Cannot Cancel", JOptionPane.ERROR_MESSAGE);
continue;
}
switch (userInput){
case "1": ...
这将捕获cancel /'x'的情况,并且continue将跳转到while循环的下一次迭代,而不是在尝试使用带有null的switch语句时抛出错误。