我已在
crontab
中尝试了以下两个选项,并期望在日志文件中仅获得 stderr
。但是,脚本文件中与 mongodump 命令相关的一些非错误行出现在日志文件中。我在这里看到了关于 stderr 管道的各种帖子,但无法得到我想要的。我哪里错了?
尝试过的两个 crontab 选项:
0 0 * * * /root/scripts/dev-vps_backup.sh >> logfile.log 2>&1 > /dev/null
0 0 * * * /root/scripts/dev-vps_backup.sh 2>&1 >> all.log | tee -a all.log err.log >&2
bash 脚本文件:
#!/bin/bash
set -e
#start time var
start_time=$(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S)
echo "Started Script: " $(basename "$0") "@ $start_time"
#########UPDATE THIS###########
### setting up variables here
######################## END of UPDATE
#create backup folders
mkdir -p $local_backupfolder
mkdir -p $local_dumps_backupfolder
mkdir -p $local_assets_backupfolder
# remote backup storage
remote_base_backupfolder=root@$remote_IP:/root/r-backups/$vps_name
# mongodump
gzfile=$local_dumps_backupfolder/$vps_name--dump--$start_time.gz
dumpMsg="$vps_name mongodump StartTime:$start_time, EndTime:"
if mongodump --gzip --archive=$gzfile ; then ### THIS generates lines that are shown in stderr file
echo "DONE: $dumpMsg $(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S)"
else
echo "ERR: $dumpMsg $(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S)" | mailx -s "ERR: $vps_name mongodump" $recipient_email
exit
fi
zipMsg1="$vps_name - $app_name1 - ZIP file for folder: $local_assets_folder1. StartTime:$start_time, EndTime:"
if zip -r $local_assets_backupfolder/$vps_name--$app_name1--assets-$(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S).zip $local_assets_folder1 ; then
echo "DONE: $zipMsg1 $(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S)"
else
echo "ERR: $zipMsg1 $(TZ=Asia/Calcutta date +%d-%m-%Y_%H-%M-%S)" | mailx -s "ERR: $vps_name - $app_name1 - assets local ZIP" $recipient_email
exit
fi
some1-some_command # to generate error
## some more lines
err.log 文件:
2024-08-02T10:33:01.116+0200 writing admin.system.version to archive '/root/backups/dumps/fvc1-vps--dump--02-08-2024_14-03-01.gz'
2024-08-02T10:33:01.118+0200 done dumping admin.system.version (1 document)
2024-08-02T10:33:01.118+0200 writing myca.syslogs to archive '/root/backups/dumps/fvc1-vps--dump--02-08-2024_14-03-01.gz'
.....some more lines related to mongodump command....
/root/scripts/fvc1-vps_backup.sh: line 61: some1-some_command: command not found
all.log 文件包含与
echo
命令和 zip
命令相关的附加行。
预期:只有 err.log 文件中的最后一行 - 这是错误。我如何实现这一目标?
更新
尝试过这个crontab:
59 11 * * * /root/scripts/fvc1-vps_backup.sh >> /root/scripts/logfile.log
生成的日志文件:
Started Script: fvc1-vps_backup.sh @ 02-08-2024_15-29-01
DONE: fvc1-vps mongodump StartTime:02-08-2024_15-29-01, EndTime: 02-08-2024_15-29-01
adding: root/jobs/assets/ (stored 0%)
adding: root/jobs/assets/tempfiles/ (stored 0%)
...... some more lines resulting from zip command.....
adding: root/jobs/assets/invoiceDocs/ (stored 0%)
DONE: fvc1-vps - jobs - ZIP file for folder: /root/jobs/assets. StartTime:02-08-2024_15-29-01, EndTime: 02-08-2024_15-29-19
日志文件不包含 mongodump 相关行。这意味着这些行将进入 stderr(如第一个日志文件结果中所示)。不知道为什么?
第二组重定向似乎适合您想要的:
shellscript 2>&1 >> all.log | tee -a all.log err.log >&2
但是,它依赖于
shellscript
中所有单独命令的输出,到达您想要的位置(stdout 或 stderr)。
看起来
mongodump
写入了 stderr。如果您希望其输出出现在 all.log
而不是 err.log
中,则需要将其 stderr 重定向到 stdout。例如:
if mongodump --gzip --archive=$gzfile 2>&1 ; then