在这个非常简单的基于PyQt的Python程序中start
按钮不起作用,似乎开始按钮和_calculateResult
方法之间没有连接。我认为_connectSignals()
方法中的某些内容是错误的,但我找不到它。你有什么想法吗?谢谢。
import sys
from PyQt5.QtCore import Qt
from PyQt5.QtWidgets import QApplication, QMainWindow, QWidget, QLineEdit, QPushButton, QHBoxLayout
class TimerUi(QMainWindow):
def __init__(self):
super().__init__()
self.setWindowTitle('Basic Timer')
self.setFixedSize(235, 235)
self.generalLayout = QHBoxLayout()
self._centralWidget = QWidget(self)
self.setCentralWidget(self._centralWidget)
self._centralWidget.setLayout(self.generalLayout)
self._createDisplayAndButtons()
def _createDisplayAndButtons(self):
self.display = QLineEdit()
self.display.setFixedHeight(35)
self.generalLayout.addWidget(self.display)
self.buttons = {}
self.buttons['start'] = QPushButton('Start')
self.buttons['start'].setFixedSize(40, 40)
self.generalLayout.addWidget(self.buttons['start'])
def setDisplayText(self, text):
self.display.setText(text)
self.display.setFocus()
class PyCalcCtrl:
def __init__(self, view):
self._view = view
self._connectSignals()
def _calculateResult(self):
self._view.setDisplayText('Time is 17:13')
def _connectSignals(self):
self._view.buttons['start'].clicked.connect(self._calculateResult)
def main():
basic_timer = QApplication(sys.argv)
view = TimerUi()
view.show()
PyCalcCtrl(view=view)
sys.exit(basic_timer.exec_())
if __name__ == '__main__':
main()
通过创建PyCalcCtrl对象,而不是将其分配给变量,然后GC将其删除。解决方案是将该对象分配给变量:
def main():
basic_timer = QApplication(sys.argv)
view = TimerUi()
view.show()
ctrl = PyCalcCtrl(view=view)
sys.exit(basic_timer.exec_())