我有一个页面,显示3列中的6个Bootstrap卡。每个Bootstrap卡都显示图像,名称,描述和页脚按钮。当用户单击Bootstrap Card页脚按钮时,一个Bootstrap Modal打开,带有一个Sql行数据ID,并进入这个Bootstrap Modal,有2个输入和一个textarea表单,如下所述:
1. <input type="text" name="name" id="name" class="form-control" required />
2. <input type="email" name="email" id="email" class="form-control" required />
3. <textarea class="form-control" type="text" name="message" id="message" rows="3"
required></textarea>
要使用尊重ID打开Modal,我在按钮卡代码中插入了一个PHP代码,如下所示:
<button type="button" class="btn btn-block btn-primary" data-toggle="modal"
data-target="#dataModal<?php echo $record['ID']; ?>">View Details</button>
其中<?php echo $record['ID']; ?>
与SQL行ID相关。
当用户填写表单并单击模态提交按钮时,所有数据都会发送到数据库,这没关系,但是在Ajax成功之后Bootstrap Modal不会隐藏。
我用来通过php代码(insert.php)在数据库中插入数据的Ajax脚本是:
<script type="text/javascript" language="javascript" >
$(document).on('submit', '#contactForm', function(event){
event.preventDefault();
$.ajax({
url:"insert.php",
method:'POST',
data:new FormData(this),
contentType:false,
processData:false,
success:function(data){
alert("Message sent!");
$("#contactForm")[0].reset();
$('#dataModal').hide();
$(".modal-backdrop").remove();
}
});
});
</script>
我认为问题与Ajax成功的这一行有关:$('#dataModal').hide();
因为Bootstrap Modal html id属性是"dataModal<?php echo $record['ID']; ?>"
而不仅仅是“dataModal”。
在这种情况下,如果我像这样$('#dataModal<?php echo $record['ID']; ?>').hide();
没有任何反应。
以下是完整的代码:
<div class="container">
<?php
include_once("includes/mysqli_connection.php");
$sql = "SELECT * FROM products ORDER BY RAND() LIMIT 6";
$resultset = mysqli_query($conn, $sql) or die("database error:". mysqli_error($conn));
while( $record = mysqli_fetch_assoc($resultset) ) {
?>
<div class="card-deck" style="width: 18rem; display:inline-block; margin:15px;">
<div class="card">
<?php echo '<img src="upload/'.$record["image"].'" class="img-thumbnail" width="286" height="180" />'; ?>
<div class="card-body" align="center"><h5 class="card-title"><?php echo $record['ProductName']; ?></h5></div>
<div class="card-footer">
<button type="button" class="btn btn-block btn-primary" data-toggle="modal" data-target="#dataModal<?php echo $record['ID']; ?>">View Details</button>
</div>
</div>
</div>
<!-- Modal -->
<div class="modal fade" id="dataModal<?php echo $record['ID']; ?>" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true" >
<div class="modal-dialog modal-lg" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" >Product: <?php echo $record['productName']; ?></h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
<div class="lead">Ask us about this product</div>
<form id="contactForm" method="post">
<div class="form-row">
<div class="col-md-4 mb-3">
<label>Name</label>
<input type="text" name="name" id="name" class="form-control" placeholder="Your name" required />
</div>
<div class="col-md-5 mb-3">
<label>E-mail</label>
<input type="email" name="email" id="email" class="form-control" placeholder="Your e-mail" required />
</div>
</div>
<div class="form-row">
<div class="col-md-12 mb-3">
<label>Message</label>
<textarea class="form-control" type="text" name="message" id="message" rows="3" placeholder="Your message" required></textarea>
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">CLOSE</button>
<button type="submit" class="btn btn-success" id="submit" >SEND</button>
</form>
</div>
</div>
</div>
</div>
<?php } ?>
</div>
<script type="text/javascript" language="javascript" >
$(document).on('submit', '#contactForm', function(event){
event.preventDefault();
$.ajax({
url:"insert.php",
method:'POST',
data:new FormData(this),
contentType:false,
processData:false,
success:function(data){
alert("Message sent!");
$("#contactForm")[0].reset();
$('#dataModal').hide();
$(".modal-backdrop").remove();
}
});
});
</script>
在这种情况下,它可能是什么,我必须做什么?谢谢大家。
编辑:如果你只想隐藏模态,你可以使用$('.modal').hide()
。
您需要在脚本中设置模态ID的值,如:
<script type="text/javascript">
var id = '#dataModal<?php echo $record['ID']; ?>';
</script>
然后你可以使用:
$(id).hide();