我有以下Java servlet:
package com.controller;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Teste extends HttpServlet {
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
request.setAttribute("teste", "Test");
request.getSession().setAttribute("teste", "Test Session");
RequestDispatcher rd = request.getRequestDispatcher("teste.jsp");
rd.forward(request, response);
}
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
@Override
public String getServletInfo() {
return "Short description";
}
}
以下web.xml
文件:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<servlet>
<servlet-name>Teste</servlet-name>
<servlet-class>com.controller.Teste</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Teste</servlet-name>
<url-pattern>/teste</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>
我可以通过url http://localhost:8084/myapp/teste
访问servlet
我想要的是将url-pattern更改为/teste/edit
,但是当我这样做,并尝试通过url http://localhost:8084/myapp/teste/edit
访问servlet时,我收到以下404错误:
HTTP状态404 - /TrabalhoPSW/teste/teste.jsp
类型状态报告
消息/TrabalhoPSW/teste/teste.jsp
description请求的资源不可用。 Apache Tomcat / 8.0.27
为什么会这样?我怎样才能解决这个问题?
问题是servlet试图找到的JSP文件。当我改变了
request.getRequestDispatcher("teste.jsp");
至
request.getRequestDispatcher("/teste.jsp");
它运作正常。
如果你需要你的servlet使用/ path和/ path / to,请将web.xml中servlet的映射更改为:
<url-pattern>/teste/*</url-pattern>