熊猫的调整间隔

Question

我在熊猫中为频率表创建了间隔。第一个间隔看起来像这样：（22，29]并从左侧打开-我只希望第一个间隔这样从两侧关闭：[22，29]。我尝试了interval [0] .closed =“ both”但没有用。

intervals = pd.interval_range(start = 22, end = 64, freq = 7)
vek_freq_table = pd.Series([0,0,0,0,0,0], index = intervals)


for x in df.loc[df.loc[:,"c"].notnull(), "c"]:
    for y in c_freq_table.index:
        if int(x) in y:
            c_freq_table.loc[y] +=1
            break

Answer 1

您必须使用列表理解（或循环）来构造自己的间隔索引：

intervals = [pd.Interval(i.left, i.right) 
             if no != 0 else pd.Interval(i.left, i.right, closed='both') 
             for (no, i) in  enumerate(intervals)]
intervals

输出：

[Interval(22, 29, closed='both'),
 Interval(29, 36, closed='right'),
 Interval(36, 43, closed='right'),
 Interval(43, 50, closed='right'),
 Interval(50, 57, closed='right'),
 Interval(57, 64, closed='right')]

---

注意：一个更简单的解决方案似乎只是更改第一个元素，例如：

new_first_elem = pd.Interval(intervals[0].left, intervals[0].right, closed='both')
intervals[0] = new_first_elem 

但是，此代码引发TypeError：

TypeError: Index does not support mutable operations