如何从随机整数数组创建序列的二维数组

Question

我有一个随机数字数组例如

[ 1 , 2 , 3 , 6 , 7 , 8 , 24 , 25 , 26 ]

此数组中有3个序列

1. [ 1  , 2  , 3  ] 
2. [ 6  , 7  , 8  ]
3. [ 24 , 25 , 26 ]

而且我需要将这些序列放入单独的2D数组中像这样

[ [ 1 , 2 , 3 ] , [ 6 , 7 , 8 ] , [ 24 , 25 , 26 ] ]

这也是我得到的，但是我无法再处理了

        val removedPositions = ArrayList<Int>()
        // Code ommited where removedPositions are filled
        val removedPositionSequence: ArrayList<ArrayList<Int>> = arrayListOf()
        var position = 0
        var currentSequence = 0
        while (position < removedPositions.size) {
            if (position + 1 < removedPositions.size) {
                var removedPositionCurrent = removedPositions[position]
                var removedPositionNext = removedPositions[position + 1]
                var foundDif = false
                while (!foundDif){

                }
                if (removedPositionCurrent + 1 == removedPositionNext) {
                    removedPositionSequence[currentSequence].add(removedPositionCurrent)
                    position++
                } else {
                    currentSequence++
                }
            }
        }

[如何做到这一点？ （首选Kotlin）

Answer 1

我假设您知道结果将是int[3][3]类型（即，由3个数组组成的数组，每个数组包含3个整数）。

我的回应基于this article，有关在Java中初始化二维数组。

int[] before = {1, 2, 3, 6, 7, 8, 24, 25, 26};
int[][] after = new int[3][3];

// iterate through "after"
for (int i = 0; i < after.length; i++) {
  for (int j = 0; j < after[i].length; j++) {
    // fill in with the correpsonding value in "before"
    after[i][j] = before[i * after.length + j];
  }
}

// print output for checking
for (int i = 0; i < after.length; i++) {
  for (int j = 0; j < after[i].length; j++) {
    System.out.print(after[i][j] + " ");
  }
  System.out.print("\n");
}

此输出

1 2 3
6 7 8
24 25 26