定义一个名为food的函数，该函数接收两个参数

Question

它应该打印：

no food
breakfast,marmalade
breakfast,coffee
lunch,dessert
dinner
no food
no food
dinner,dessert

 def food(input,boolean):
    time = int(input)
    food_type = ""
    if time >= 0 and time < 6 or time >= 22:
        food_type = "no food"
    if time >= 6 and time <= 10:
        food_type = "breakfast"
    if time >= 11 and time <= 15:
        food_type = "lunch"
    if time >= 16 and time < 22:
        food_type = "dinner"
    dessert = ""
    if boolean == True and food_type == "breakfast":
        dessert = "marmalade"
    if boolean == False and food_type == "breakfast":
        dessert = "coffee"
    if boolean == True and food_type == "lunch":
        dessert = "dessert"
    if boolean == True and food_type == "dinner":
        dessert = "dessert"
    return ','.join((food_type, dessert)) 

[基本上现在，我在return''之间有一个逗号，因此它将显示breakfast, marmalade，但是当涉及到no food时，它将在末尾添加一个逗号，因此看起来像no food,

它看起来像：

no food
breakfast,marmalade
breakfast,coffee
lunch,dessert
dinner
no food
no food
dinner,dessert

Answer 1

我不确定要输出的内容是否100％，但我想即使dessert为food_type为"no food"还是boolean为True，也不要使用逗号C0]。我至少可以想到两种不同的方法。

第一种方法是替换

    food_type = "no food"

with

    return "no food"

另一种方法是替换

  return ','.join((food_type, dessert))

with

  output = food_type
  if output != "no food":
    output = ','.join((food_type, dessert))
  return output

有些人会喜欢第二个，因为只有一个return。