Ajax在php循环中更新我表单中的第一行

Question

我正在使用PHP while循环。在我的while循环中，我有一个HTML表单。我正在通过ajax将表单值处理到我的PHP中，然后在我的数据库中更新这些值。问题是每当我提交该表单时它只更新我表中的第一个获取的行。我也通过我的表单将唯一的Id传递给ajax但由于某种原因，只有第一行不断更新。

我的Php代码：

<?php
$data = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($data as $row) { ?><form>
    <input type="text" name="id" value="<?php echo $row['no'] ?>"><br>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio" value="NO">NO
            <input type="radio" name="optradio" value="YES">YES
        </div>
    </fieldset>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio1" value="NO">NO
            <input type="radio" name="optradio1" value="YES">YES
        </div>
    </fieldset>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio2" value="NO">NO
            <input type="radio" name="optradio2" value="YES">YES
        </div>
    </fieldset>
    <button type="submit" value="Submit" class="btn">SUBMIT</button>
</form><?php }

我的Ajax代码：

$(document).ready(function(){

 var launchAjax = function () { // event handler for button click
 $.post(
 "inbetween.php/",
  {
      id: $("[name=id]").val(),
      question: $("[name=optradio]:checked").val(),
      question1: $("[name=optradio1]:checked").val(),
      question2: $("[name=optradio2]:checked").val(),
  }
);
}
    $(".btn").click(launchAjax);
 }); 

我的PHP SQL查询

 <?php

include 'common.php';

$id = filter_input(INPUT_POST, "id", FILTER_SANITIZE_NUMBER_INT);
$question = filter_input(INPUT_POST, "optradio", FILTER_SANITIZE_STRING);
$question1 = filter_input(INPUT_POST, "optradio1", FILTER_SANITIZE_STRING);
$question2 = filter_input(INPUT_POST, "optradio2", FILTER_SANITIZE_STRING);


function getMark($answer, $mark = 1){ 
    $result = 0;
    if($answer == 'YES'){
        $result = $mark;
    }
    return $result;
}

    $p = 0;
    $p += getMark($question, 1); 
    $p += getMark($question1, .5);
    $p += getMark($question2, 2);


$command1 = "UPDATE rating SET marks = marks + '$c', marks= marks/ totalNumber WHERE no = '$id'";

 // prepare and executing
$stmt1 = $dbh->prepare($command1);
$result = $stmt1->execute();

?>

Answer 1

您正在使用PDO，但您的while循环似乎使用mysqli方法，如果您选择多行使用fetchAll，请更新您的代码：

$data = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($data as $row) {
    $id = $row['no'];
}

更新：如果你想要多个表单，每行一个，你必须这样做：

<?php
$data = $stmt->fetchAll(PDO::FETCH_ASSOC);
foreach ($data as $row) { ?><form>
    <input type="text" name="id" value="<?php echo $row['no'] ?>"><br>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio" value="NO">NO
            <input type="radio" name="optradio" value="YES">YES
        </div>
    </fieldset>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio1" value="NO">NO
            <input type="radio" name="optradio1" value="YES">YES
        </div>
    </fieldset>
    <fieldset>
        <div>
            <label>XYZ Question</label>
        </div>
        <div>
            <input type="radio" name="optradio2" value="NO">NO
            <input type="radio" name="optradio2" value="YES">YES
        </div>
    </fieldset>
    <button type="submit" value="Submit" class="btn">SUBMIT</button>
</form><?php }