根据列表顺序排序对象数组[重复]

Question

这个问题在这里已有答案：

• Sort an object array by custom order 5个答案

大家好，我有排序的任务。这是交易：我有一个数组

arr = [{role:'mom', name:'a'}, {role:'dad', name:'d'}, {role:'bro', name: 'c'}]

并排序序列表sortSequence = ['dad','mom','bro']所以根据这个列表我需要一个输出数组相等

arr = [{role:'dad', name:'d'}, {role:'mom', name:'a'}, {role:'bro', name: 'c'}]

如何使用sort方法来做到这一点？

const sortAccordingList = (list, arr) => {
    //... ?
}

Answer 1

您可以使用indexOf获取角色的索引

var sortSequence = ['dad', 'mom', 'bro'];
var arr = [{role:'mom', name:'a'}, {role:'dad', name:'d'}, {role:'bro', name: 'c'}];

arr.sort((a, b) => sortSequence.indexOf(a.role) - sortSequence.indexOf(b.role));

console.log(arr);

---

您也可以将sortSequence作为对象。这将使得更容易获得排序顺序。喜欢：

var sortSequence = {dad:1,mom:2,bro:3};
var arr = [{role:'mom', name:'a'}, {role:'dad', name:'d'}, {role:'bro', name: 'c'}];

arr.sort((a, b) => sortSequence[a.role] - sortSequence[b.role]);

console.log(arr);