如何在由多个点创建的曲面上找到 xyz 位置。假设我测量了一个向两个方向倾斜的停车场的周界,不一定是在平面上创建一个表面。如果我走到点周边的任何区域,GPS 设备会告诉我纬度和经度?我将如何计算该点到地面的高程? 使用 C#
The common method is a bilinear interpolation below:
using System;
using System.Linq;
class SurfaceInterpolation
{
static void Main()
{
// Assume you have a list of survey points with latitude, longitude, and elevation
var surveyPoints = new[]
{
new SurveyPoint(0, 0, 100),
new SurveyPoint(0, 1, 150),
new SurveyPoint(1, 0, 200),
new SurveyPoint(1, 1, 250)
// Add more survey points as needed
};
// Example: Calculate elevation at a specific point
double latitude = 0.5; // Example latitude
double longitude = 0.5; // Example longitude
double elevation = InterpolateElevation(surveyPoints, latitude, longitude);
Console.WriteLine($"Elevation at ({latitude}, {longitude}): {elevation}");
}
static double InterpolateElevation(SurveyPoint[] surveyPoints, double targetLatitude, double targetLongitude)
{
// Find the four nearest survey points
var nearestPoints = surveyPoints.OrderBy(p => Math.Pow(p.Latitude - targetLatitude, 2) + Math.Pow(p.Longitude - targetLongitude, 2)).Take(4).ToArray();
// Bilinear interpolation
double q11 = nearestPoints[0].Elevation;
double q21 = nearestPoints[1].Elevation;
double q12 = nearestPoints[2].Elevation;
double q22 = nearestPoints[3].Elevation;
double x1 = nearestPoints[0].Latitude;
double x2 = nearestPoints[1].Latitude;
double y1 = nearestPoints[0].Longitude;
double y2 = nearestPoints[2].Longitude;
double x = targetLatitude;
double y = targetLongitude;
double elevation = (1.0 / ((x2 - x1) * (y2 - y1))) *
(q11 * (x2 - x) * (y2 - y) +
q21 * (x - x1) * (y2 - y) +
q12 * (x2 - x) * (y - y1) +
q22 * (x - x1) * (y - y1));
return elevation;
}
}
class SurveyPoint
{
public double Latitude { get; }
public double Longitude { get; }
public double Elevation { get; }
public SurveyPoint(double latitude, double longitude, double elevation)
{
Latitude = latitude;
Longitude = longitude;
Elevation = elevation;
}
}