递归cte查询|创建多个编号行| Sql-server

Question

我正在尝试用数字0900000000000000000000000007165中的字段填写表中的一列到数字0900000000000000000000000000000008165

我有一个问题，对于这段代码来说，这些数字太大了，我不知道该怎么办

类型：ID-varchar（31）

错误：（翻译）

消息240，第16级，状态1，第3行在循环“ cter”查询的“开始”列中，锚点与循环部分之间的类型不匹配。

  with cter as (
     select 0900000000000000000000000007165 as start, 0900000000000000000000000008165 as loop_end
     union all
     select c.start + 1, loop_end
     from cter c
     where c.start < loop_end
)

INSERT INTO [Base].[dbo].[Table] (Id)
   select c.start
   from cter c
   option (maxrecursion 0);

Answer 1

您将获得算术溢出错误，因为即使对于bigint数据类型，此值也太大。

我建议您将其视为字符并删除前缀，然后再添加前缀，如@ Tyron78所建议的

DECLARE @loop_start CHAR(31) = '0900000000000000000000000007165'
, @loop_end CHAR(31) = '0900000000000000000000000008165'
;with cter as 
(
     select CAST(RIGHT(@loop_start,4) as int) as start, CAST(RIGHT(@loop_end,4) AS INT) loop_end
     union all
     select c.start + 1, loop_end
     from cter c
     where c.start < loop_end
)

   select CONCAT(LEFT(@loop_start,27), c.start)
   from cter c
   option (maxrecursion 0);

结果集是：

+---------------------------------+
| 0900000000000000000000000007165 |
| 0900000000000000000000000007166 |
|                               . |
|                               . |
|                               . |
| 0900000000000000000000000008163 |
| 0900000000000000000000000008164 |
| 0900000000000000000000000008165 |
+---------------------------------+