为什么多次调用calloc导致我的应用程序崩溃?

问题描述 投票:0回答:1

我有一个函数初始化一个包含嵌套结构和数组的结构。初始化结构时,我多次调用calloc

请参阅下面的代码:

typedef struct
{
    int length;
    uint8_t *buffer;
} buffer_a;

typedef struct
{
    int length;
    uint8_t *buffer;
    int *second_buffer_size;
    uint8_t **second_buffer;
} buffer_b;

typedef struct
{
    int max_length;
    buffer_a *buffer_in;
    buffer_b *buffer_out;
} state_struct;


state_struct *init(int size, int elements) {
    size_t struct_size = sizeof(state_struct);
    state_struct *s = (state_struct*) calloc(struct_size, struct_size);

    log("Building state with length %d", size);

    s->max_length = size;

    size_t buffer_in_size = s->max_length * sizeof(buffer_a);
    s->buffer_in = (buffer_a*) calloc(buffer_in_size, buffer_in_size);

    size_t buffer_out_size = s->max_length * sizeof(buffer_b);
    s->buffer_out = (buffer_b*) calloc(buffer_out_size, buffer_out_size);

    log("Allocated memory for both buffers structs");

    for (int i = 0; i < s->max_length; ++i) {
        size_t buf_size = elements * sizeof(uint8_t);

        s->buffer_in[i].buffer = (uint8_t*) calloc(buf_size, buf_size);
        s->buffer_in[i].length = -1;
        log(s, "Allocated memory for in buffer");

        s->buffer_out[i].buffer = (uint8_t*) calloc(buf_size, buf_size);
        s->buffer_out[i].length = -1;
        log(s, "Allocated memory for out buffer");

        size_t inner_size = elements * elements * sizeof(uint8_t);
        size_t inner_second_buffer_size = elements * sizeof(int);    
        s->buffer_out[i].second_buffer = (uint8_t**) calloc(inner_size, inner_size);
        s->buffer_out[i].second_buffer_size = (int*) calloc(inner_second_buffer_size, inner_second_buffer_size);
        log(s, "Allocated memory for inner buffer");
    }

    return s;
}

仅打印for循环之前的日志,但是程序崩溃,并且循环内的第一个log语句也没有输出。

为什么会这样?

c memory memory-management java-native-interface
1个回答
0
投票

因此,这可能不是您所提问题的答案,但是这里有:当我运行此代码(在Ubuntu,gcc 7.4上)并将所有log函数替换为printf时,它成功完成了。我怀疑问题可能出在您使用日志功能的方式上。您指定它可以工作直到循环内的第一个日志调用。您没有指定log函数的功能,也没有指定它是printf的函数还是宏包装器,但是您在循环内部以不同的方式调用它-第一个参数是*state_struct而不是格式字符串。

而且,您的calloc呼叫方式在语义上似乎不正确。第一个参数应该是您要分配的第二个参数大小的块数(在这种情况下大概为1)

© www.soinside.com 2019 - 2024. All rights reserved.