我可以在 Python 中以支持/尊重/理解其所有者的继承层次结构的方式实现通用描述符吗?
代码中应该更清楚:
from typing import (
Generic, Optional, TYPE_CHECKING,
Type, TypeVar, Union, overload,
)
T = TypeVar("T", bound="A") # noqa
class Descr(Generic[T]):
@overload
def __get__(self: "Descr[T]", instance: None, owner: Type[T]) -> "Descr[T]": ...
@overload
def __get__(self: "Descr[T]", instance: T, owner: Type[T]) -> T: ...
def __get__(self: "Descr[T]", instance: Optional[T], owner: Type[T]) -> Union["Descr[T]", T]:
if instance is None:
return self
return instance
class A:
attr: int = 123
descr = Descr[T]() # I want to bind T here, but don't know how
class B(A):
new_attr: int = 123
qwerty: str = "qwe"
if __name__ == "__main__":
a = A()
if TYPE_CHECKING:
reveal_type(a.descr) # mypy guess it is T? but I want A*
print("a.attr =", a.descr.attr) # mypy error: T? has no attribute "attr"
# no runtime error
b = B()
if TYPE_CHECKING:
reveal_type(b.descr) # mypy said it's T? but I want B*
print("b.new_attr =", b.descr.new_attr) # mypy error: T? has no attribute "new_attr"
# no runtime error
print("b.qwerty =", b.descr.qwerty) # mypy error: T? has no attribute "qwerty"
# (no runtime error)
gist - gist 上几乎相同的代码片段
我不确定您是否需要将描述符类设为通用;在
__get__
的实例上使用 Type[T]
可能就足以返回 T
:
T = TypeVar("T") # noqa
class Descr:
@overload
def __get__(self, instance: None, owner: Type[T]) -> "Descr": ...
@overload
def __get__(self, instance: T, owner: Type[T]) -> T: ...
def __get__(self, instance: Optional[T], owner: Type[T]) -> Union["Descr", T]:
if instance is None:
return self
return instance
class A:
attr: int = 123
descr = Descr()
class B(A):
new_attr: int = 123
qwerty: str = "qwe"
你的每个例子都按你想要的方式工作,你将会得到一个错误
print("b.spam =", b.descr.spam)
产生
error: "B" has no attribute "spam"