我已经创建了自己的简单 jQuery 插件,但是当我放置 2 个元素并在每个元素上调用该插件时,我遇到了一些问题。
这是我的
.js
代码:
function fTable(element,options) {
self = this;
this.$element = $(element);
this.table = $(this.$element).find('table');
this.thead = $(this.table).find('thead');
this.tbody = $(this.table).find('tbody');
column = options.column;
this.defaults = {
}
// Merge default options with user options
this.options = $.extend(true, {}, this.defaults, options);
this.init();
}
fTable.prototype = {
init : function() {
self = this;
this.td = $(this.thead).find('tr td:first');
$(this.td).html('<a class="add">Plus</a>');
this.bindEvents();
},
bindEvents : function() {
self = this;
console.log(this.table);
$(this.table).on('click', '.add', function(){
$row = '<tr>';
$row += '<td></td>';
$.each(column, function(index, value){
$row += '<td><input type="text" value="" name='+value.name+' '+value.prop+'></td>';
});
$row += '</tr>';
console.log(self);
$($row).appendTo(self.table);
lastTR = $(self.tbody).find('tr:last');
$(lastTR).find('td:first').html('<a class="remove">Remove</a>');
});
$(this.table).on('click', '.remove', function(){
row = $(this).closest('tr');
$(row).remove();
});
}
}
$.fn.fTable = function(options) {
return this.each(function() {
new fTable(this,options);
});
}
$('.crud').fTable({
column:[
{'type':'text','name':'NIK','prop':'disabled'},
{'type':'text','name':'NAME','prop':''},
]
});
$('.crud2').fTable({
column:[
{'type':'text','name':'NIK','prop':'disabled'},
{'type':'text','name':'NAME','prop':''},
]
});
HTML:
<div class="crud">
<table class="table table-bordered">
<thead>
<tr>
<td style="width:10%"></td>
<td>NIK</td>
<td>Name</td>
</tr>
</thead>
<tbody>
<tr>
<td></td>
<td>1</td>
<td>Ardhi</td>
</tr>
<tr>
<td></td>
<td>2</td>
<td>Mega</td>
</tr>
</tbody>
</table>
</div>
<div class="crud2">
<table class="table table-bordered">
<thead>
<tr>
<td style="width:10%"></td>
<td>NIK</td>
<td>Name</td>
</tr>
</thead>
<tbody>
<tr>
<td></td>
<td>1</td>
<td>Zaphire</td>
</tr>
<tr>
<td></td>
<td>2</td>
<td>Rexa</td>
</tr>
</tbody>
</table>
</div>
问题是当我单击第一个表(class='crud')上的“加号”时,它将向第二个表(class='crud2')而不是第一个表(class='crud')添加新行
有什么帮助吗?
你的范围有问题。在您的
bindEvents
原型函数中,您声明 self=this
但您没有引用当前作用域。事实上,你到处都存在范围问题。 请查看 JavaScript 范围。
将该行更改为
var self
或什至更好的 let self
以获取函数范围,而不是任何更高的(全局)或之前声明的 self。
function fTable(element,options){
let self = this; // you omitted let or var here
this.$element = $(element);
this.table = $(this.$element).find('table');
this.thead = $(this.table).find('thead');
this.tbody = $(this.table).find('tbody');
this.column = options.column; // it was omitted here also but for sake of consistency, I applied column as a member to fTable.
this.defaults = {
}
//Merge default options with user options
this.options = $.extend(true, {}, this.defaults, options);
this.init();
}
fTable.prototype = {
init : function(){
let self = this; // omitted here too
this.td = $(this.$element).find('tr td:first');
$(this.td).html('<a class="add">Plus</a>');
this.bindEvents();
},
bindEvents : function(){
let self = this;
$(this.table).on('click', '.add', function(){
let $row = '<tr>';
$row += '<td></td>';
$.each(self.column, function(index, value){
$row += '<td><input type="text" value="" name='+value.name+' '+value.prop+'></td>';
});
$row += '</tr>';
$($row).appendTo(self.table);
let lastTR = $(self.tbody).find('tr:last');
$(lastTR).find('td:first').html('<a class="remove">Remove</a>');
});
$(this.table).on('click', '.remove', function(){
let row = $(self).closest('tr');
$(row).remove();
});
}
}
$.fn.fTable = function(options){
var self = this; // and here
return this.each(function(){
new fTable(self,options);
});
}
$('.crud').fTable({
column:[
{'type':'text','name':'NIK','prop':'disabled'},
{'type':'text','name':'NAME','prop':''},
]
});
$('.crud2').fTable({
column:[
{'type':'text','name':'NIK','prop':'disabled'},
{'type':'text','name':'NAME','prop':''},
]
});