合并多个数组php

Question

我真的需要一些帮助来解决这个问题。

我有很多数组，我想合并其中一些。如下所示。

            while ($row = $db->fetch_array($result_set)) {
                $year           = $row['year(Tidspunkt)'];
                $month_num      = $row['month(Tidspunkt)'];
                $month      = $cal->name_of_month($row['month(Tidspunkt)']);
                $type           = $row['Klubtype'];
                $visits         = $row['count(Handling)'];
                $days_in_month = $cal->days_in_month($month_num,$year);
                $avg           = $visits / $days_in_month;
                $object_array[]= array('month' => $month , 'visits' => $visits, 'type' => $type, 'avg' => $avg);
            }
            return $month_array;

输出看起来像这样

Array ( 
     [0] => Array ( [month] => Januar [visits] => 891 [type] => FK [avg] => 28.7419354839 ) 
     [1] => Array ( [month] => Januar [visits] => 23 [type] => UK [avg] => 0.741935483871 ) 
)

现在我想根据月份的值合并这两个数组。想象一下当我有一整年的阵列时。那么最好有 12 个数组而不是 24 个。

谢谢你帮助我。

Answer 1

我想这可能就是你想要的......

$newArray = array();

foreach($array as $value) {

   $month = $value['month'];
   unset($value['month']);
   $newArray[$month][] = $value;
}

这会给你一些类似...

Array ( 
     ['Januar'] => Array (
        [0] => Array( [visits] => 891 [type] => FK [avg] => 28.7419354839 ) 
        [1] => Array ( [visits] => 23 [type] => UK [avg] => 0.741935483871 ) 
)

Answer 2

我建议使用 GROUP BY 和聚合函数在 SQL 层中执行所有计算。

迭代结果集时，将每个唯一月份的引用变量推入结果数组中。然后，您只需将行数据推送为由月份值标识的引用的新子级。

PHPize 在线演示

$danishMonths = [
    1 => 'Januar',
    2 => 'Februar',
    3 => 'Marts',
    4 => 'April',
    5 => 'Maj',
    6 => 'Juni',
    7 => 'Juli',
    8 => 'August',
    9 => 'September',
    10 => 'Oktober',
    11 => 'November',
    12 => 'December'
];

$sql = <<<SQL
SELECT 
    YEAR(Tidspunkt) year,
    MONTH(Tidspunkt) month_num,
    Klubtype type,
    COUNT(Handling) visits,
    COUNT(Handling) / DAY(LAST_DAY(MIN(Tidspunkt))) avg_visits
FROM visits
WHERE YEAR(Tidspunkt) = '2024'
GROUP BY year, month_num, type
ORDER BY year, month_num, type
SQL;

$month_array = [];
foreach ($mysqli->query($sql) as $row) {
    if (!isset($ref[$row['month_num']])) {
        $month_array[] =& $ref[$row['month_num']];
    }
    $ref[$row['month_num']][] = [
        'month' => $danishMonths[$row['month_num']],
        'visits' => $row['visits'],
        'type' => $row['type'],
        'avg' => $row['avg_visits']
    ];
}
var_export($month_array);

使用我的假样本数据，这是输出的结构：

array (
  0 => 
  array (
    0 => 
    array (
      'month' => 'Januar',
      'visits' => '3',
      'type' => 'FK',
      'avg' => '0.0968',
    ),
    1 => 
    array (
      'month' => 'Januar',
      'visits' => '2',
      'type' => 'UK',
      'avg' => '0.0645',
    ),
  ),
  1 => 
  array (
    0 => 
    array (
      'month' => 'Februar',
      'visits' => '2',
      'type' => 'FK',
      'avg' => '0.0690',
    ),
    1 => 
    array (
      'month' => 'Februar',
      'visits' => '1',
      'type' => 'UK',
      'avg' => '0.0345',
    ),
  ),
)