未固定页面重新加载sqlite3nodejs

问题描述 投票:0回答:0

你知道为什么吗?

提前感谢您!

<div class="game-footer"> <div class="button-add-rem"> <button wii-game-button></button> </div> </div> <!-- The button is not on a FORM -->

// This is the event Listener gameButton.addEventListener("click", (e) => { fetch(`http://localhost:3000/ajoutsuppr?gameID=${gameID}`) .then(resp => resp.json()) .then(data => { if(data.result === false){ console.log("Was not on list, added") } else { console.log("Was on list, deleted") } }) .catch(error => { console.log('Error when request :', error); }); });

app.get('/ajoutsuppr', (req, res) => { const gameID = req.query.gameID; // Recover game ID db.get(`SELECT * FROM gamelist WHERE id = ?`, [gameID], (err, row) => { if (err) { console.error('Error :', err.message); } else { if (row) { // This part make the page reloading db.run(`DELETE FROM gamelist WHERE id = ?`, [gameID], (err) => { if (err) return console.error("Erro during inserting id to database: ", err.message); }); res.json({result: true}) //If game was in the list, then delete } else { // This part make the page reloading db.run(`INSERT INTO gamelist VALUES (?,?)`, [gameID, Date.now()], (err) => { if (err) return console.error("Error during inserting id to database: ", err.message); }); //else, i add it res.json({result: false}) } } }); });

我期望每次我使用
db.run
函数时都不会重新加载页面
	
您可以使用event.preventdefault()取消事件。


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