我正在用C编写一个程序，该程序计算对基金的年利息，并确定可以授予多少1000、500和250美元的奖学金。
[如果可能，基金应奖励5笔$ 1000的奖学金，10笔$ 500的奖学金以及250英镑的剩余资金。如果这不可能，该基金将尽可能地提供$ 1000和$ 500的奖学金。例如，如果他们有$ 4,750，他们将奖励4个$ 1000奖学金，1个$ 500奖学金和1个$ 250奖学金。
即凭借$ 15,000的资金，该基金可以授予5个$ 1000的奖学金，10个$ 500的奖学金和20 $ 250的奖学金。该程序应为用户打印此信息。
我有2个问题。
问题1：此问题需要多少个变量？我可以想到Amount_in_fundInterestpercent_RATEscholarship1000scholarship500scholarship250我是否缺少变量来解决此问题？
问题2：获得scholarship1000值的正确方程式是什么？正如您在我的代码中看到的那样，我的方程式有误
我一直在弄乱这段代码。
#include <stdio.h>
int main (){
double Amount_in_fund = 0 ;
int yearly_INTEREST = 0, percent_RATE, scholarship1000 = 0, scholarship500 = 0, scholarship250 = 0;
//takes data and saves it in Amount_in_fund
printf("How much was in the fund last year?\n");
scanf("%lf", &Amount_in_fund);
//takes data and saves it in percent_RATE
printf("What is the yearly percentage rate?\n");
scanf("%d", &percent_RATE);
if(scholarship1000 < 5){
yearly_INTEREST = (Amount_in_fund * percent_RATE)/100;
scholarship1000 = yearly_INTEREST / 1000; //***** What would be the right equation here?**
printf("%d $1000 scholarships will be awarded.\n", scholarship1000);
}
else if(scholarship1000 >= 5){
printf("5 $1000 scholarships will be awarded.\n");
}
system("pause");
return 0;
}
由于Sankalp Bhamare而更新了代码：更新后的代码未在变量twoHundredFiftyScholarship中获得期望的值。
使用调试器时，我看到唯一不正确的值是变量twoHundredFiftyScholarship。
进入样本运行＃1时变量twoHundredFiftyScholarship的期望值应为1。我得到的值为3。
与样品运行＃2相同。期望值为8。我得到的值为48。
示例运行＃1
去年基金里有多少钱？
40000
每年的百分比是多少？
2
将授予0美元$ 1000的奖学金。
将授予1 500美元的奖学金。
将颁发1 250美元的奖学金。
示例运行＃2
去年基金里有多少钱？
1200000
每年的百分比是多少？
1
将授予5项$ 1000的奖学金。
将颁发10个$ 500的奖学金。
将颁发8项$ 250的奖学金。
进入样本运行＃2时变量twoHundredFiftyScholarship的期望值应为8。我得到的值为48。
#include <stdio.h>
#include <stdlib.h>
int main(){
double fundAmount;
int yearlyInterestRate;
double yearlyInterest;
double remainingScholarship;
int thousandScholarships = 0;
int fiveHundredScholarship = 0;
int twoHundredFiftyScholarship = 0;
printf("How much was in the fund last year?\n");
scanf("%lf", &fundAmount);
printf("What is the yearly percentage rate?\n");
scanf("%d", &yearlyInterestRate);
yearlyInterest = fundAmount*yearlyInterestRate/100.0;
remainingScholarship = yearlyInterest;
thousandScholarships = remainingScholarship/1000.0;
fiveHundredScholarship = remainingScholarship/500.0;
twoHundredFiftyScholarship = remainingScholarship/250.0;
if(thousandScholarships > 5){
thousandScholarships = 5;
remainingScholarship -= thousandScholarships*1000.0;}
if(fiveHundredScholarship > 10){
fiveHundredScholarship = 10;
remainingScholarship -= fiveHundredScholarship*500;}
remainingScholarship -= twoHundredFiftyScholarship*250;
printf("%d $1000 scholarships will be awarded.\n",thousandScholarships);
printf("%d $500 scholarships will be awarded.\n",fiveHundredScholarship);
printf("%d $250 scholarships will be awarded.\n",twoHundredFiftyScholarship);
system("pause");
return 0;
}
您可以简单地实现上述内容：
#include <stdio.h>
int main()
{
double fundAmount = 100350.0;
double yearlyInterestRate = 9.0;
double yearlyInterest = fundAmount*yearlyInterestRate/100.0;
double remainingScholarship = yearlyInterest;
int thousandScholarships = remainingScholarship/1000.0;
if(thousandScholarships > 5)
thousandScholarships = 5;
remainingScholarship -= thousandScholarships*1000.0;
int fiveHundredScholarship = remainingScholarship/500.0;
if (fiveHundredScholarship > 10)
fiveHundredScholarship = 10;
remainingScholarship -= fiveHundredScholarship*500;
int twoHundredFiftyScholarship = remainingScholarship/250.0;
remainingScholarship -= twoHundredFiftyScholarship*250;
printf("$1000 Scholarships : %d\n",thousandScholarships);
printf("$500 Scholarships : %d\n",fiveHundredScholarship);
printf("$250 Scholarships : %d\n",twoHundredFiftyScholarship);
printf("Residual Amount : %lf\n",remainingScholarship);
return 0;
}
问题1：此问题需要多少个变量？
这个问题没有道理。假设您有一个变量声明为int x;，则可以编写代码
int x1 = x;
int x2 = x*1;
int x3 = x+0;
int x4 = x|0;
然后x，x1，x2，x3，x4都包含相同的整数值，并且可以互换使用。
还要想象您有两个变量和代码
int x= something();
int y= x+1;
然后（如果以后不更改y，则可以用y代替出现的x+1。
请务必阅读有关C编程语言（特别是Modern C）和How to debug small programs的更多信息。