var res=[
{
"id":1,
"type_name":"Weight",
"type_abbr":"wt",
"uoms":[
{
"id":1,
"unit_abbr":"sh tn",
"unit_name":"Short Tons",
"created_at":"2017-06-07 00:35:06",
"updated_at":"2018-05-24 23:34:25",
"uom_type_id":1
},
{
"id":3,
"unit_abbr":"g",
"unit_name":"Grams",
"created_at":"2017-06-07 00:35:06",
"updated_at":"2018-05-24 23:34:25",
"uom_type_id":1
}
]
}
]
我正在尝试遍历每个结果并获取嵌套的uoms.unit_name
并将它们注入到新数组中。下面是我的非工作代码。预先谢谢你。
res.forEach((uom) => {
const uomsArr = uom.uoms.map(uoms => uoms.uoms);
});
您可以使用reduce
:
var res = [{
"id": 1,
"type_name": "Weight",
"type_abbr": "wt",
"uoms": [{
"id": 1,
"unit_abbr": "sh tn",
"unit_name": "Short Tons",
"created_at": "2017-06-07 00:35:06",
"updated_at": "2018-05-24 23:34:25",
"uom_type_id": 1
},
{
"id": 3,
"unit_abbr": "g",
"unit_name": "Grams",
"created_at": "2017-06-07 00:35:06",
"updated_at": "2018-05-24 23:34:25",
"uom_type_id": 1
}
]
},
{
"id": 2,
"type_name": "Weight",
"type_abbr": "wt",
"uoms": [{
"id": 11,
"unit_abbr": "sh tn",
"unit_name": "Short Tons",
"created_at": "2017-06-07 00:35:06",
"updated_at": "2018-05-24 23:34:25",
"uom_type_id": 11
},
{
"id": 31,
"unit_abbr": "g",
"unit_name": "Grams",
"created_at": "2017-06-07 00:35:06",
"updated_at": "2018-05-24 23:34:25",
"uom_type_id": 31
}
]
}
]
console.log(res.reduce((a, r) => [...a.concat(r.uoms)], []))