如何保存单选按钮的状态？

Question

我试图保存我的单选按钮的状态，但它不适合我任何想法如何做到这一点？我现在正在使用userdefaults

class WTSettingsVC: UIViewController {


    @IBOutlet weak var checkBttn: DLRadioButton!
    @IBOutlet weak var checkBttn2: DLRadioButton!
    var switchON : Bool = false
    var button : Bool = false
    let defaults = UserDefaults.standard
    override func viewDidLoad() {
        super.viewDidLoad()

        checkBttn.isSelected = UserDefaults.standard.bool(forKey: "issaved")
        checkBttn2.isSelected = UserDefaults.standard.bool(forKey: "issaved")

    }

    override func viewWillAppear(_ animated: Bool) {
        super .viewWillAppear(animated)
         self.setCommonNavigationBar(title: "Settings", largeTitle: true, tranpernt: false, tint: WTConstant.LMColors.greenTheme, fontColor: .white)
        checkBttn?.isEnabled =  UserDefaults.standard.bool(forKey: "switchState")
        checkBttn?.addTarget(self, action: #selector(bttnAction(_:)), for: .touchUpInside)
    }

    @IBAction func bttnAction(_ sender: DLRadioButton) {
        if sender.tag == 1  {
           sender.isEnabled = true
             switchON = true
             defaults.set(switchON, forKey: "switchON")


        }else if sender.tag == 2{
            sender.isEnabled = true
            switchON = false
            defaults.set(switchON, forKey: "switchON")


                }
            }
        }

        UserDefaults.standard.set(sender.isEnabled, forKey: "switchState")
        UserDefaults.standard.synchronize()

    }

}

Answer 1

不要使用相同的键来存储两个按钮的状态。并使用相同的键来存储和检索按钮的状态。

class WTSettingsVC: UIViewController {

    @IBOutlet weak var checkBttn: DLRadioButton!
    @IBOutlet weak var checkBttn2: DLRadioButton!

    override func viewDidLoad() {
        super.viewDidLoad()

        checkBttn.isSelected = UserDefaults.standard.bool(forKey: "checkBttnSelected")
        checkBttn2.isSelected = UserDefaults.standard.bool(forKey: "checkBttn2Selected")
        checkBttn.addTarget(self, action: #selector(bttnAction(_:)), for: .touchUpInside)
        checkBttn2.addTarget(self, action: #selector(bttnAction(_:)), for: .touchUpInside)
    }

    @IBAction func bttnAction(_ sender: DLRadioButton) {
        if sender == checkBttn  {
            UserDefaults.standard.set(true, forKey: "checkBttnSelected")
            UserDefaults.standard.set(false, forKey: "checkBttn2Selected")
        }else if sender == checkBttn2 {
            UserDefaults.standard.set(false, forKey: "checkBttnSelected")
            UserDefaults.standard.set(true, forKey: "checkBttn2Selected")
        }
    }
}

Answer 2

看起来您的代码显然是嵌套不当。例如，以下代码实际上没有在bttnAction函数中执行：

UserDefaults.standard.set(sender.isEnabled, forKey: "switchState")
UserDefaults.standard.synchronize()

此代码需要放在它上面的大括号内。尝试重写您的代码，类似于：

class WTSettingsVC: UIViewController {


    @IBOutlet weak var checkBttn: DLRadioButton!
    @IBOutlet weak var checkBttn2: DLRadioButton!
    var switchON : Bool = false
    var button : Bool = false
    let defaults = UserDefaults.standard
    override func viewDidLoad() {
        super.viewDidLoad()

        checkBttn.isSelected = UserDefaults.standard.bool(forKey: "issaved")
        checkBttn2.isSelected = UserDefaults.standard.bool(forKey: "issaved")

    }

    override func viewWillAppear(_ animated: Bool) {
        super.viewWillAppear(animated)
        self.setCommonNavigationBar(title: "Settings", largeTitle: true, tranpernt: false, tint: WTConstant.LMColors.greenTheme, fontColor: .white)
        checkBttn?.isEnabled =  UserDefaults.standard.bool(forKey: "switchState")
        checkBttn?.addTarget(self, action: #selector(bttnAction(_:)), for: .touchUpInside)
    }

    @IBAction func bttnAction(_ sender: DLRadioButton) {
        if sender.tag == 1 {
            sender.isEnabled = true
            switchON = true
            defaults.set(switchON, forKey: "switchON")


        } else if sender.tag == 2 {
            sender.isEnabled = true
            switchON = false
            defaults.set(switchON, forKey: "switchON")
        }
        UserDefaults.standard.set(sender.isEnabled, forKey: "switchState")
        UserDefaults.standard.synchronize()
    }
}

因为这些代码行在该函数的结束括号之外，所以这些行实际上并未包含在任何函数中，因此永远不会被调用。