如何在颤动中对齐扁平按钮？

Question

我想知道如何在颤动中对齐按钮。我是不熟悉的新手，对于当前代码，我无法抛出任何行，列或换行。我想以垂直方式对齐我的按钮，但当前将其水平对齐并给我显示“ RIGHT OVER BY 256 PIXELS”显示错误

                  return showDialog<void>(
                      context: context,
                      builder: (BuildContext context) {
                        return AlertDialog(
                          content: Text("You have $counts routes!"),
                          actions: <Widget>[
                            new FlatButton(
                              textColor: Colors.black,
                              padding:
                                  EdgeInsets.fromLTRB(20, 0, 0, 10),
                              child: Text(
                                  "This is route 1! \n" +
                                      rList[0] + "\n"),
                              onPressed: () {},
                            ),
                            new FlatButton(
                              textColor: Colors.black,
                              padding:
                                  EdgeInsets.fromLTRB(20, 0, 0, 10),
                              child: Text(
                                  "This is your second route! \n" +
                                      rList[1] + "\n"),
                              onPressed: () {},
                            ),
                          ],
                        );
                      });

Answer 1

只需将按钮添加到Column

actions: <Widget>[
    Column(
        crossAxisAlignment: CrossAxisAlignment.end,
        children: <Widget>[
            button,
            button
        ]
    )
],