我想从php对象类添加自定义属性

问题描述 投票:0回答:2

我想为每个对象添加新属性。我的代码如下所示:

 function getCitationDataofquotes($var1){
    $query = "SELECT `id`,`title`,`source`,`content`,`page`,`city`,`publisher` FROM `#__gpo_citations_quotes`";
    $query .= " WHERE `id`='" . $var1 . "'";
    if (!empty($query))
    {
        $some= array();
        $this->_db->setQuery($query);
        $data = $this->_db->loadObject();
        return $data; 

    }
 $value = $datapages->getCitationDataofquotes($var1);
 $getdataofcitation['citations'][] = $value;

然后我的输出返回数据如下

{id: "12091",
title: "Homicide Victims by Year and Jurisdiction, 1989–90 to 2010–12",
source: "Homicide in Australia: 2010–11 to 2011–12: National Homicide Monitoring Program report",
content: " ACT = Australian Capital Territory]",
page: "p. 37",
city: "Canberra",
publisher: "Australian Institute of Criminology"
},

{
id: "8901",
title: "test",
source: null,
content: "",
page: null,
city: null,
publisher: null
},

现在我想为每个对象添加新属性。我希望每个对象都有这个输出。

{ id: "8901",
 title: "test",
 source: null,
 content: "",
 page: null,
 city: null,
 publisher: null ,
 **new property: something**}
php mysql
2个回答
0
投票

首先,您的$查询容易受到Sql注入攻击。 BTW有多种方法可以达到你想要的效果。例如,您可以在查询中添加属性:

SELECT 'some value' As `some_field` ...

如果你想在php代码中添加它,你可以像@madalinivascu上面说的那样动态添加它:

如果它是一个对象:

$myObject->myNewProperty = 'My new value'; 
# if it is dynamically and you don't know the name ...
$myObject->{"myNewProperty"} = 'My new value'; 

如果是数组:

$myArray['myNewProperty'] = 'My new value';

0
投票

当带有多个带数组的对象返回值时更新此代码

 $value[] = $datapages->getCitationDataofquotes($var1);

                for($i=0; $i<count($value); $i++) 
                {
                    $value[$i]->newprop = 'new content';
                }
© www.soinside.com 2019 - 2024. All rights reserved.