如何在Python中分割音频文件以使其具有小于特定尺寸的块？

Question

我需要将音频文件划分为小于 25mb 的块。

我不想将文件保存在磁盘上。

这是我现在的代码，但它没有按预期工作，因为它将音频分割成大约 2mb 的块

def audio_splitter(audio_file)
    audio = AudioSegment.from_file(audio_file)

    # Set the chunk size and overlap
    target_chunk_size = 20 * 1024 * 1024  # Target chunk size in bytes (20 MB)
    # Overlap in milliseconds (10 seconds)
    overlap_duration = 10 * 1000
    # Estimate the number of bytes per millisecond in the audio
    bytes_per_ms = len(audio.raw_data) / len(audio)
    # Calculate duration of each chunk in milliseconds
    chunk_duration = int(target_chunk_size / bytes_per_ms)

    chunks = []
    start = 0
    while start < len(audio):
        end = start + chunk_duration
        chunk = audio[start:end]
        chunks.append(chunk)
        start += chunk_duration - overlap_duration

    for i, chunk in enumerate(chunks):
        chunk.export(f"chunk_{i + 1}.mp3", format="mp3")

我认为

len(audio.raw_data)

有问题，因为它似乎没有返回正确的字节大小。

有没有更好的方法来解决这个问题？

Answer 1

您可以使用

bytes.IO

估计 在我的测试用例中，我使用了 1/2 mb 限制，并且文件都完全正确

512kb,512kb,426kb,71.1kb

from pydub import AudioSegment
import io
import sys
import os



def audio_splitter(audio_file):
    audio = AudioSegment.from_file(audio_file)

    test = audio[0:len(audio)]
    test_io = io.BytesIO()
    test.export(test_io, format="mp3")
    test_size = sys.getsizeof(test_io)


    # Set the chunk size and overlap
    target_chunk_size = 20 * 1024 * 1024  # Target chunk size in bytes (20 MB)
    # Overlap in milliseconds (10 seconds)
    overlap_duration = 10 * 1000
    # Estimate the number of bytes per millisecond in the audio
    bytes_per_ms = test_size/len(audio) # Estimation
    # Calculate duration of each chunk in milliseconds
    chunk_duration = int(target_chunk_size / bytes_per_ms)

    chunks = []
    start = 0
    while start < len(audio):
        end = start + chunk_duration
        chunk = audio[start:end]
        chunks.append(chunk)
        start += chunk_duration - overlap_duration

    for i, chunk in enumerate(chunks):
        chunk.export(f"chunk_{i + 1}.mp3", format="mp3")

if __name__ == "__main__":
    audio_splitter(*sys.argv[1:])