SpringBoot中通过构造函数表示的不满意依赖性

问题描述 投票:0回答:1

嗨,我的springboot版本是'2.2.4.RELEASE'。我想在构造函数中自动装配2参数。但它不起作用。马比,我认为“ passwordEncoder”有问题...这是'UserService.java'代码。

import kr.co.loosie.foody.domain.User;
import kr.co.loosie.foody.domain.UserRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.security.crypto.password.PasswordEncoder;
import org.springframework.stereotype.Service;

import javax.transaction.Transactional;
import java.util.Optional;



@Service
@Transactional
public class UserService {

private UserRepository userRepository;
private PasswordEncoder passwordEncoder;


@Autowired
public UserService(UserRepository userRepository,
                   PasswordEncoder passwordEncoder) {
    this.userRepository = userRepository;
    this.passwordEncoder = passwordEncoder;
}

public User registerUser(String email, String name, String password) {
    Optional<User> existed = userRepository.findByEmail(email);
    if (existed.isPresent()) {
        throw new EmailExistedException(email);
    }

    String encodedPassword = passwordEncoder.encode(password);

    User user = User.builder()
            .email(email)
            .name(name)
            .password(encodedPassword)
            .level(1L)
            .build();
    return userRepository.save(user);
}



public User authenticate(String email, String password) {
    User user = userRepository.findByEmail(email)
            .orElseThrow(() -> new EmailNotExistedException(email));

    if (!passwordEncoder.matches(password, user.getPassword())) {
        throw new PasswordWrongException();
    }

    return user;
  }
 }

错误部分在这里。@Autowiredpublic UserService(UserRepository userRepository,PasswordEncoder passwordEncoder){this.userRepository = userRepository;this.passwordEncoder = passwordEncoder;}

当我仅使用UserReposiotory进行自动连线时,它就可以工作但是我把PasswordEncoder passwordEncoder行放了,这行不通。请给我一些帮助!

这是警告消息

Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with         
name 'userService' defined in file [D:\CCC\intellij_ex\foody\foody-customer- 
api\build\classes\java\main\kr\co\loosie\foody\application\UserService.class]: Unsatisfied dependency 
expressed through constructor parameter 1; nested exception is 
org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type 
'org.springframework.security.crypto.password.PasswordEncoder' available: expected at least 1 bean 
which qualifies as autowire candidate. Dependency annotations: {}

请给我一些帮助!

java spring spring-boot service autowired
1个回答
0
投票

错误消息显示org.springframework.security.crypto.password.PasswordEncoder没有bean,这意味着您在任何地方都没有定义它。

您将需要类似的东西:

@Bean
    public PasswordEncoder passwordEncoder() {
        return new BCryptPasswordEncoder();
    }

在您的配置中(如果通过Java配置)

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