如何在按下按钮后延迟一行代码

Question

我是Java新手，正在尝试在用户按下按钮后延迟一行代码。该行代码增加了数组[[i ++。我想这样做的原因是因为我正在通过使两个textView动画化。一个textView淡出，而另一个text淡入，我试图通过仅增加数组索引来改变显示的单词，因为它们具有相同的Alpha，即动画设置持续时间500的一半。看到有人建议使用swing timer，而另一些建议使用thread.sleep。有什么建议？这是该按钮的代码：）。

public void nextWord(View view) { //nextWord is the onclick of the button


        Button nextButton = findViewById(R.id.nextButton);
        Button showTextButton = findViewById(R.id.showTextButton);
        TextView wordTextView = findViewById(R.id.wordTextView);
        EditText editTextView = findViewById(R.id.enterEditText);
        ImageView logoImageView = findViewById(R.id.logoImageView);
        TextView wordTextView1 = findViewById(R.id.wordTextView1);


        i++; // need to delay this


        String displayHint;
        String displayText;

        displayText = enterWord() + chooseArray();
        displayHint = chooseArray();

        wordTextView.setText(displayText);
        editTextView.setHint(displayHint);
        wordTextView1.setText(displayText) ;



        enteredWords[i] = editTextView.getText().toString();

        if (i%2 == 0) {
            ObjectAnimator alphaAnimation = ObjectAnimator.ofFloat(wordTextView, View.ALPHA, 1f, 0f);
            alphaAnimation.setDuration(1000);
            ObjectAnimator otherAlphaAnimation = ObjectAnimator.ofFloat(wordTextView1, View.ALPHA, 0f, 1f);
            otherAlphaAnimation.setDuration(1000);

            AnimatorSet animatorSet = new AnimatorSet();
            animatorSet.playTogether(otherAlphaAnimation,alphaAnimation);
            animatorSet.start();

        } else {
            ObjectAnimator alphaAnimation = ObjectAnimator.ofFloat(wordTextView, View.ALPHA, 0f, 1f);
            alphaAnimation.setDuration(1000);
            ObjectAnimator otherAlphaAnimation = ObjectAnimator.ofFloat(wordTextView1, View.ALPHA, 1f, 0f);
            otherAlphaAnimation.setDuration(1000);

            AnimatorSet animatorSet = new AnimatorSet();
            animatorSet.playTogether(otherAlphaAnimation,alphaAnimation);
            animatorSet.start();
        }


    }

Answer 1

尝试使用

new Handler().postDelayed(Runnable r, long delay)

使用方式
new Handler().postDelayed(new Runnable() {
                        @Override
                        public void run() {
                            // fade in new text view
                        }
                    }, 1000);   // time needed for first animation to finish

现在，当第一个动画需要1000毫秒才能完成时，第二个动画也将在1000毫秒之后开始。您可以将其放入final值中，以立即操纵这些延迟以使其保持同步