我是Android开发的新手,我正尝试通过使用“身份验证方法-> POST https://notify-api.line.me/api/notify”(LINE Notify API Document)将消息发送到LINE通知服务
这是我的密码,我总是会得到
返回状态码:-1
。请帮助我找出问题出在哪里?
LINENotify.java] >>
package com.example.test3; import java.io.BufferedWriter; import java.io.OutputStream; import java.io.OutputStreamWriter; import java.net.HttpURLConnection; import java.net.URL; import javax.net.ssl.HttpsURLConnection; public class LINENotify { private static final String strEndpoint = "https://notify-api.line.me/api/notify"; private static final String tokenKEY = "ldO3dTIAjT5OpjWbeZAQtnXhq23poCXcEAvKoTwJHhn"; public int sendMSG( String message ) { int statusCode; statusCode = -1; try { URL url = new URL( strEndpoint ); HttpsURLConnection connection = (HttpsURLConnection) url.openConnection(); connection.setRequestMethod( "POST" ); connection.addRequestProperty("Authorization", "Bearer " + tokenKEY); connection.addRequestProperty("Content-Type", "application/x-www-form-urlencoded"); connection.setConnectTimeout(15*1000); connection.setDoOutput( true ); connection.setUseCaches( false ); connection.connect(); connection.setReadTimeout(15*1000); connection.setDoInput( true ); OutputStream os = connection.getOutputStream(); BufferedWriter writer = new BufferedWriter( new OutputStreamWriter( os, "UTF-8") ); writer.write( "message=" + message ); writer.flush(); writer.close(); os.close(); statusCode = connection.getResponseCode(); if ( statusCode == 200 ) { // } else { throw new Exception( "Error:(StatusCode)" + statusCode + ", " + connection.getResponseMessage() ); } connection.disconnect(); } catch (Exception e) { e.printStackTrace(); } return statusCode; } }
activity_main.xml
<?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:app="http://schemas.android.com/apk/res-auto" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" tools:context=".MainActivity"> <EditText android:id="@+id/editText" android:layout_width="match_parent" android:layout_height="wrap_content" android:ems="10" android:inputType="textPersonName" android:text="Name" /> <Button android:id="@+id/button" android:layout_width="match_parent" android:layout_height="wrap_content" android:text="Button" /> </LinearLayout>
AndroidManifest.xml
<?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.example.test3"> <application android:allowBackup="true" android:icon="@mipmap/ic_launcher" android:label="@string/app_name" android:roundIcon="@mipmap/ic_launcher_round" android:supportsRtl="true" android:theme="@style/AppTheme"> <activity android:name=".MainActivity"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-permission android:name="android.permission.INTERNET"></uses-permission> </manifest>
MainActivity.java
package com.example.test3;
import androidx.appcompat.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
public class MainActivity extends AppCompatActivity implements View.OnClickListener {
EditText msg;
Button send;
LINENotify lineNotify;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
msg = (EditText) findViewById(R.id.editText);
send = (Button) findViewById(R.id.button);
lineNotify = new LINENotify();
send.setOnClickListener(this);
}// onCreate
@Override
public void onClick(View v) {
switch( v.getId() ) {
case R.id.button: {
int statusCode = lineNotify.sendMSG( msg.getText().toString() );
Toast.makeText(this, "Return status code: " + statusCode, Toast.LENGTH_LONG).show();
break;
}
}
}
}
我是Android开发的新手,我正在尝试通过使用“身份验证方法-> POST https://notify-api.line.me/api/notify”将消息发送到LINE通知服务(LINE通知API文档)...
我得到了答案!感谢Google和张贴他们的经验和笔记的人。