我需要在该查询上使用split_part函数:
CREATE TABLE client_group_by_group_test AS SELECT *, SPLIT_PART( groupe,
',', 1 ) AS group1, SPLIT_PART(SPLIT_PART(groupe,',',2),',',-1) AS
group2, SPLIT_PART(SPLIT_PART(groupe,'',3),'',-3) AS group3,
SPLIT_PART(groupe,'',-4) AS group4 FROM planification_client
但它给了我以下错误:
错误:字段位置必须大于零
那么,我怎样才能在这里处理负值?
这种reverse(split_part(reverse(col_A), '_'::text, 1))
的声明能起作用吗?我正在引用that question。
编辑:我完全坚持这个查询。
更多细节:我有一个列有“服务器名称”,另一个列有不同的组用逗号分隔。
server name| group |
-----------+------------------------------+
XPTERTBIEP9|GRNW_SPO_S_F_H, GRNW_SPO_S_I_J|
我需要得到的输出是,如果服务器有多个组,它们需要在group1,group2等不同的列中...
server name| group |group1 |group 2
-----------+------------------------------+--------------+--------------
XPTERTBIEP9|GRNW_SPO_S_F_H, GRNW_SPO_S_I_J|GRNW_SPO_S_F_H|GRNW_SPO_S_I_J
如果负数应该表示从结尾的偏移量,则两步法可能更好:
CREATE TABLE client_group_by_group_test
AS
SELECT ...,
agroups[1] as group1,
agroups2[cardinality(agroups2) - 1] as groups2,
agroups3[cardinality(agroups3) - 3] as groups3,
agroups[cardinality(agroups) - 4] as group4
from (
select *,
string_to_array(groupe, ',') as agroups,
(string_to_array(string_to_array(groupe, ','), ',')[2]) as agroups2,
(string_to_array(string_to_array(groupe, ','), ',')[3]) as agroups3,
from planification_client
) t
请注意,您需要在最外面的SELECT列出所需的列以排除中间的“agroups”列。