我目前在Project Euler中遇到问题17。一点背景:我的程序适用于数字1- 120.一旦我超过120,它不按照我的意图使用模运算符。我正在尝试修复它,但是对于此问题的先前迭代,除法和余数函数正常工作,所以我试图找出导致条件错误的更改(I> = 120 && I < 1000)(Ps,不关心优化,我是一名编程学生,只是致力于创建和熟悉数组)。谢谢!
我尝试在不同的时间使用我的除法和余数运算符,例如s + = [division(I)]对(I> = 120 && I <1000)条件并且没有修复错误。
public class LetterCount {
public static void main(String[] args) {
int i;
String[] ones = {"","one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten","eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", ""};
String[] tens = {"", "","twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety", ""};
String[] hundreds = {"","onehundred", "twohundred", "threehundred", "fourhundred", "fivehundred", "sixhunded", "sevenhundred", "eighthundred", "ninehundred"};
String[] thousand = {"", "onethousand"};
String s = new String();
for(i = 0; i <= 126; i++) {
if(i <= 20) {
s+= ones[i];
}
if(i == 20) {
//performs i / 10
s+= tens[division(i)];
}
if(i > 20 && i < 100) {
//performs i / 10 & i % 10
s+= tens[division(i)];
s+= ones[remainder(i)];
} if (i == 100) {
//performs i / 100
s+= hundreds[division(i)];
} if (i > 100 && i < 120) {
//performs i / 10, i % 10, and i / 100
s+= hundreds[division(i)];
s+= tens[division(i)];
s+= ones[remainder(i)];
} if (i >= 120 && i < 1000) {
//performs i / 100, i / 10, and i % 10
s+= hundreds[division(i)];
s+= tens[division(i)];
s+= ones[remainder(i)];
} if (i == 1000) {
s+= thousand[division(i)];
}
}
System.out.println(s);
}
public static int remainder(int i) {
if (i >= 100 && i <= 1000) {
return i % 100;
} else if(i > 10 && i < 100) {
return i % 10;
}
return i;
}
public static int division(int i) {
if (i == 1000) {
return i / 1000;
}
if (i >= 100 && i <= 1000) {
return i / 100;
} if (i < 100) {
return i / 10;
}
return i;
}
}
你的ones
数组长度= 21
所以你可以访问它的最后一个元素是ones[20]
但是在你的函数remainder(int i)
中,你可以返回最多99的值
因为你的方法包含这行return i % 100;
所以当你使用ones[remainder(i)];
时
如果返回的提醒值> 20,您将正常面对Array Index Out of Bounds